I'm fetching pokemon names and images, and storing them like this.
const pokemon = $(el)
.find(".pokemon")
.toArray()
.map((el) => {
const name = $(el).attr("title") || "";
const image = $(el).find("img").attr("src") || "";
return { name, image };
});
I want a seperate variable that sorts by most reoccurring and then removes duplicates.
I tried using byCount() from this:
Array.prototype.byCount = function () {
var itm,
a = [],
L = this.length,
o = {};
for (var i = 0; i < L; i++) {
itm = this[i];
if (!itm) continue;
if (o[itm] == undefined) o[itm] = 1;
else ++o[itm];
}
for (var p in o) a[a.length] = p;
return a.sort(function (a, b) {
return o[b] - o[a];
});
};
and it worked if i fetch the name / image separately, but doesn't seem to work on an object. the data is like
[name1, name1, name2, name3, name3, name4]
[img1, img1, img2, img3, img3, img4]
if i sort them individually using byCount() they don't always align so it might return:
[name1, name3, name2, name4]
[img3, img1, img2, img4]
since both img1 & img3 have the same occurance count.
const repeatedItems = {}
arrayOfObjects.forEach((item) => {
if (repeatedItems[item.name]) {
repeatedItems[item.name] = { ...item, count: repeatedItems[item.name].count++ }
} else {
repeatedItems[item.name] = { ...item, count: 1 }
}
})
const sortedArr = Object.values(repeatedItems).sort((a, b) => a.count - b.count).map((item) => ({ name: item.name, image: item.image }))
To sort words with the prototype sort, use the localeCompare String prototype:
items.sort((a, b) => a.localeCompare(b))