Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

263
Visualizações
Iterate over objects and return key-value pairs from an array in Javascript

I am trying to iterate over a JSON object and return values to another function.

enter image description here

I would like to pass each value of quadrant1_x, quadrant1_y...quadrant4_y of its respective object to the calculatePlot() function. But I get an error Uncaught TypeError: user is undefined

Javascript looks like this:

function generateRandomUser() {
  const user = consumeAPI()
  return calculatePlot(user)
}

function consumeAPI() {
  const graphs = @json($graphs); //received from the backend (Laravel)

  for (let i = 0; i < graphs.length; i++) {
    graphs.forEach((value, key) => {
      console.log([key, value]);
      return {
        x1: (value.quadrant1_x * range),
        y1: (value.quadrant1_y * range),
        x2: (value.quadrant2_x * range),
        y2: (value.quadrant2_y * range),
        x3: (value.quadrant3_x * range),
        y3: (value.quadrant3_y * range),
        x4: (value.quadrant4_x * range),
        y4: (value.quadrant4_y * range),
      }
    })
  }

  function calculatePlot(user) {
    return [{
      x: center + user.x1,
      y: center - user.y1
    }, {
      x: center + user.x2,
      y: center - user.y2
    }, {
      x: center + user.x3,
      y: center - user.y3
    }, {
      x: center + user.x4,
      y: center - user.y4
    }]
  }

  for (let i = 0; i < maxUsers; i++) {
    let plot = generateRandomUser();
    let label = `Mid-point`;
    addUser(plot, label);
    calculateMidPoint(plot);
  }

This code is generating a cartesian plot as an SVG. So, each quadrant value of x & y is required in order to render a graph.

Sample : JSFiddle

about 4 years ago · Juan Pablo Isaza
3 Respostas
Responde à pergunta

0

Looks like you're consumeAPI method doesn't return anything. So when you invoke it, the value is undefined.

Also, there is no point in putting a forEach loop inside of the for loop that iterates over the same iterable...

Not sure why you're iterating within the consume api. In fact, it's unclear why you're iterating at all.

Try returning your values:

async function consumeAPI() { // This will probably require async/await.
  const graphs = await @json($graphs); 
  return graphs;
}

Using a loop inside generateRandomUser wouldn't be logical, because it seems your goal is to get a random user. If you'd like to get a random user (item in the array), you could try something like this:

function generateRandomUser() {
   
   const users = consumeAPI()
   var randomItem = users[Math.floor(Math.random()*users.length)]

   return users[randomItem];
}

I'm thinking all the extra loops and whatnot aren't necessary.

about 4 years ago · Juan Pablo Isaza Relatório

0

Putting the return inside of a forEach will simply break out of the loop and not return anything. This is why consumeAPI returns undefined. As @silencedogood mentioned, there is no need for a forEach inside of the for loop.

You can use Array.map as an alternative and transform each object inside of the array in case there are more objects that need to be handled.

If graphs is an array of objects that you wish to transform, you can simply do: graphs.map(graph => {x1: graph.quadrant1_x * range ....}); and return the transformed array.

about 4 years ago · Juan Pablo Isaza Relatório

0

Okay, So after spending some time on basics I realized it was quite straightforward.

Learnings:

  1. Move the incoming backend response out from consumeAPI()
  2. Pop-out values of each object from it.
  3. Return the Object to calculatePlot() function.

So now the consumeAPI() looks like this.

     function consumeAPI() {
            const value = sample_graphs.pop();

            const x_1 = value.quadrant1_x;
            const y_1 = value.quadrant1_y;
            const x_2 = value.quadrant2_x;
            const y_2 = value.quadrant2_y;
            const x_3 = value.quadrant3_x;
            const y_3 = value.quadrant3_y;
            const x_4 = value.quadrant4_x;
            const y_4 = value.quadrant4_y;

            let retObj = {
                x1: x_1 * range,
                y1: y_1 * range,
                x2: x_2 * range,
                y2: y_2 * range,
                x3: x_3 * range,
                y3: y_3 * range,
                x4: x_4 * range,
                y4: y_4 * range,
            };

            return retObj;
           
        }

Rest remains the same.

 function generateRandomUser() {
            const user = consumeAPI();
            return calculatePlot(user);
        }
let sample_graph = [
 {
                quadrant1_x: "0.17",
                quadrant2_x: "0.53",
                quadrant3_x: "-0.48",
                quadrant4_x: "-0.86",
                quadrant1_y: "0.31",
                quadrant2_y: "-0.21",
                quadrant3_y: "-0.60",
                quadrant4_y: "0.50",
            },
    ...

];

// consumeAPI() goes here

for (let i = 0; i < maxUsers; i++) {
            let plot = generateRandomUser();
            addUser(plot);
            calculateMidPoint(plot);
        }

Sample: JSFiddle

about 4 years ago · Juan Pablo Isaza Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda