Is it possible to see the callee/caller of a function when use strict is enabled?
'use strict';
function jamie (){
console.info(arguments.callee.caller.name);
//this will output the below error
//uncaught TypeError: 'caller', 'callee', and 'arguments' properties may not be accessed on strict mode functions or the arguments objects for calls to them
};
function jiminyCricket (){
jamie();
}
jiminyCricket ();For what it's worth, I agree with the comments above. For whatever problem you're trying to solve, there are usually better solutions.
However, just for illustrative purposes, here's one (very ugly) solution:
'use strict'
function jamie (){
var callerName;
try { throw new Error(); }
catch (e) {
var re = /(\w+)@|at (\w+) \(/g, st = e.stack, m;
re.exec(st), m = re.exec(st);
callerName = m[1] || m[2];
}
console.log(callerName);
};
function jiminyCricket (){
jamie();
}
jiminyCricket(); // jiminyCricket
I've only tested this in Chrome, Firefox, and IE11, so your mileage may vary.
Please note that this should not be used in production. This is an ugly solution, which can be helpful for debugging, but if you need something from the caller, pass it as argument or save it into a accessible variable.
The short version of @p.s.w.g answer(without throwing an error, just instantiating one):
let re = /([^(]+)@|at ([^(]+) \(/g;
let aRegexResult = re.exec(new Error().stack);
sCallerName = aRegexResult[1] || aRegexResult[2];
Full Snippet:
'use strict'
function jamie (){
var sCallerName;
{
let re = /([^(]+)@|at ([^(]+) \(/g;
let aRegexResult = re.exec(new Error().stack);
sCallerName = aRegexResult[1] || aRegexResult[2];
}
console.log(sCallerName);
};
function jiminyCricket(){
jamie();
};
jiminyCricket(); // jiminyCricketIt does not worked for me Here is what I finally do, just in case it helps someone
function callerName() {
try {
throw new Error();
}
catch (e) {
try {
return e.stack.split('at ')[3].split(' ')[0];
} catch (e) {
return '';
}
}
}
function currentFunction(){
let whoCallMe = callerName();
console.log(whoCallMe);
}