Can anyone assist in sorting the below array in ascending / descending order? The array is to be sorted based on the highest number in each grouping (grouped using brand). Numbers in each group are to be sorted as well:
original_array = [
{ brand: "Ford", number: "1", },
{ brand: "BMW", number: "1", },
{ brand: "BMW", number: "5", },
{ brand: "BMW", number: "20",},
{ brand: "Toyota", number: "10",}
];
desc_order = [
{ brand: "BMW", number: "20",},
{ brand: "BMW", number: "5", },
{ brand: "BMW", number: "1", },
{ brand: "Toyota", number: "10",},
{ brand: "Ford", number: "1", }
];
asc_order = [
{ brand: "Ford", number: "1", },
{ brand: "Toyota", number: "10",},
{ brand: "BMW", number: "1", },
{ brand: "BMW", number: "5", },
{ brand: "BMW", number: "20",}
];
Since the order of the brands in the output depends on maximum values in their group, I would suggest to first create an object that lists the maximum number per brand.
Then use that to sort by, using the following sequence of ordering:
Implementation:
const array = [ { brand: "Ford", number: "1", }, { brand: "BMW", number: "1", }, { brand: "BMW", number: "5", }, { brand: "BMW", number: "20", }, { brand: "Toyota", number: "10", } ];
// First collect the maximum values per brand as an aggregate:
const aggr = {};
for (let {brand, number} of array) {
aggr[brand] = Math.max(number, aggr[brand] ?? number);
}
// Ascending
array.sort((a, b) => aggr[a.brand] - aggr[b.brand]
|| a.brand.localeCompare(b.brand)
|| a.number - b.number);
console.log(array);
// Descending
array.sort((a, b) => aggr[b.brand] - aggr[a.brand]
|| b.brand.localeCompare(a.brand)
|| b.number - a.number);
console.log(array);