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How to group certain objects in array of objects?

var list = [{
        'orderSeries': 26342,
        'make': 'audi',
        'model': 'r8',
        'year': '2012'
    }, {
        'orderSeries': 26342,
        'make': 'audi',
        'model': 'rs5',
        'year': '2013'
    }, {
        'orderSeries': null,
        'make': 'ford',
        'model': 'mustang',
        'year': '2012'
    }, {
        'orderSeries': null,
        'make': 'ford',
        'model': 'fusion',
        'year': '2015'
    }, {
        'orderSeries': null,
        'make': 'kia',
        'model': 'optima',
        'year': '2012'
    }];

Is it possible to group the first 2 objects in this array because the orderSeries value is the same, and the rest of the objects to not be grouped by orderSeries property because the value for those is null?

and to get a format of the array like this when its grouped:

var list = [{
        'orderSeries': 26342,
        'make': 'audi',
        cars: [
            { 'model': 'r8', 'year': '2012'},
            {'model': 'rs5', 'year': '2013'}
        ]
    }, 
    {
        'orderSeries': null,
        'make': 'ford',
        'model': 'mustang',
        'year': '2012'
    }, {
        'orderSeries': null,
        'make': 'ford',
        'model': 'fusion',
        'year': '2015'
    }, {
        'orderSeries': null,
        'make': 'kia',
        'model': 'optima',
        'year': '2012'
    }]

about 4 years ago · Juan Pablo Isaza

3 Respostas

Responde à pergunta

0

Using Array#reduce, iterate over list while updating two arrays, one for orders with orderSeries and another without it
Using Array#reduce again, iterate over the first list with orderSeries while updating a Map to group the items by the orderSeries
The resulting list will include the grouped list and the ones without orderSeries

const list = [ { 'orderSeries': 26342, 'make': 'audi', 'model': 'r8', 'year': '2012' }, { 'orderSeries': 26342, 'make': 'audi', 'model': 'rs5', 'year': '2013' }, { 'orderSeries': null, 'make': 'ford', 'model': 'mustang', 'year': '2012' }, { 'orderSeries': null, 'make': 'ford', 'model': 'fusion', 'year': '2015' }, { 'orderSeries': null, 'make': 'kia', 'model': 'optima', 'year': '2012'  }];

const [ordersWithSeries, ordersWithoutSeries] = list.reduce(([a, b], order) => 
  order.orderSeries ? [[...a, order], b] : [a, [...b, order]]
, [[], []]);

const groupedOrdersBySeries = [...
  ordersWithSeries.reduce((orderSeriesMap, { orderSeries, make, model, year }) => {
    const order = orderSeriesMap.get(orderSeries);
    if(!order) {
      orderSeriesMap.set(orderSeries, { orderSeries, make, cars: [{ model, year }] });
    } else {
      order.cars.push({ model, year });
    }
    return orderSeriesMap;
  }, new Map)
  .values()
];

const res = [...groupedOrdersBySeries, ...ordersWithoutSeries ];

console.log(res);

about 4 years ago · Juan Pablo Isaza Relatório

0

I would simply manipulate original data one by one using for loop.

const list = [{
    orderSeries: 26342,
    make: "audi",
    model: "r8",
    year: "2012"
  },
  {
    orderSeries: 26342,
    make: "audi",
    model: "rs5",
    year: "2013"
  },
  {
    orderSeries: null,
    make: "ford",
    model: "mustang",
    year: "2012"
  },
  {
    orderSeries: null,
    make: "ford",
    model: "fusion",
    year: "2015"
  },
  {
    orderSeries: null,
    make: "kia",
    model: "optima",
    year: "2012"
  }
];

let mergeIndexes = [];
let newList = [];

const placeholder = {
  orderSeries: null,
  make: "",
  cars: []
};

for (let i = 0; i <= list.length - 1; i++) {

  // continue if current index is already merge with the previous
  if (mergeIndexes.includes(i.toString())) continue;
  const item = list[i];
  const filter = list.filter((i) => i.orderSeries === item.orderSeries);
  if (filter.length && Boolean(item.orderSeries)) {
    placeholder.orderSeries = filter[0].orderSeries;
    placeholder.make = filter[0].make;
    placeholder.cars = filter.reduce(
      (prev, curr) => [...prev, {
        model: curr.model,
        year: curr.year
      }], []
    );
    newList = [...newList, placeholder];
    // to keep track of the indexes that are already merge
    mergeIndexes = [...mergeIndexes, ...Object.keys(filter)];
  } else {
    newList = [...newList, item];
  }
}
console.log(newList);

about 4 years ago · Juan Pablo Isaza Relatório

Responde à pergunta

Encontrar trabalhos remotos

Accepted Answer · 2022-07-10T23:15:55.007Z

I would use just forEach and fill new list with some modifications

const list = [{
  'orderSeries': 26342,
  'make': 'audi',
  'model': 'r8',
  'year': '2012'
}, {
  'orderSeries': 26342,
  'make': 'audi',
  'model': 'rs5',
  'year': '2013'
}, {
  'orderSeries': null,
  'make': 'ford',
  'model': 'mustang',
  'year': '2012'
}, {
  'orderSeries': null,
  'make': 'ford',
  'model': 'fusion',
  'year': '2015'
}, {
  'orderSeries': null,
  'make': 'kia',
  'model': 'optima',
  'year': '2012'
}];

const groupedList = [];

list.forEach(item => {
  if (!item.orderSeries) {
    groupedList.push(item);
  } else {
    const existingGroup = groupedList.find(i => i.orderSeries === item.orderSeries);

    if (existingGroup) {
      existingGroup.cars.push({ model: item.model, year: item.year });
    } else {
      groupedList.push({
        orderSeries: item.orderSeries,
        make: item.make,
        cars: [
          { model: item.model, year: item.year }
        ]
      });
    }
  }
});

console.log(groupedList);

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How to group certain objects in array of objects?

3 Respostas

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Encontrar trabalhos remotos

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