This code generates errors and I want to replace only first 3 over 4 match
https://jsfiddle.net/9Lfj0dva/
let test = ". . . .";
const regex = /\./gm;
let matchAll = test.matchAll(regex);
console.log(Array.from(matchAll).length);
const replacements = [1, 2, 3];
test = test.replace(regex, () => replacements.next().value);
console.log(test);
Something like this:
let test = ". . . .";
const regex = /\./m;
const replacements = [1, 2, 3];
replacements.forEach((replacement) => test = test.replace(regex, replacement));
console.log(test);I remove the global flag from the regular expression to only replace the first match found, and then loop through the replacements array.
1)
You can initialize the couter to 0 and then replace it with replacement array data until index < length - 1
let test = ". . . .";
const regex = /\./gm;
let matchAll = [...test.matchAll(regex)];
const replacements = [1, 2, 3];
let index = 0;
const length = matchAll.length;
const result = test.replace(regex, (match) => index < length - 1 ? replacements[index++] : match );
console.log(result);2) If you want to generalise it then you can add one more condition index < replacements.length
let test = ". . . . . .";
const regex = /\./gm;
let matchAll = [...test.matchAll(regex)];
const length = matchAll.length;
const replacements = [1, 2, 3];
let index = 0;
const result = test.replace(regex, (match) =>
index < length - 1 && index < replacements.length
? replacements[index++]
: match
);
console.log(result);