Python's dictionaries have no order, so indexing like you are suggesting (fruits[2]) makes no sense as you can't retrieve the second element of something that has no order. They are merely sets of key:value pairs.

To retrieve the value at key: 'kiwi', simply do: fruit['kiwi']. This is the most fundamental way to access the value of a certain key. See the documentation for further clarification.

And passing that into a print() call would actually give you an output:

print(fruit['kiwi'])
#2.0

Note how the 2.00 is reduced to 2.0, this is because superfluous zeroes are removed.

Finally, if you want to use a for-loop (don't know why you would, they are significantly more inefficient in this case (O(n) vs O(1) for straight lookup)) then you can do the following:

for k, v in fruit.items():
    if k == 'kiwi':
        print(v)
#2.0

fruit = {
    "banana": 1.00,
    "apple": 1.53,
    "kiwi": 2.00,
    "avocado": 3.23,
    "mango": 2.33,
    "pineapple": 1.44,
    "strawberries": 1.95,
    "melon": 2.34,
    "grapes": 0.98
}

for key,value in fruit.items():
    if value == 2.00:
         print(key)

I think you are looking for something like this.

It's too late but none of the answer mentioned about dict.get() method

>>> print(fruit.get('kiwi'))
2.0

In dict.get() method you can also pass default value if key not exist in the dictionary it will return default value. If default value is not specified then it will return None.

>>> print(fruit.get('cherry', 99))
99

fruit dictionary doesn't have key named cherry so dict.get() method returns default value 99