how to remove price last six zeros in react native
original price - ₹699 original price - ₹800
API response - ₹699000000 API response - ₹800000000
I try this. it removes all zeros.
var numstr = 800000000
while (numstr[numstr.length-1] === "0") {
numstr = numstr.slice(0, -1)
if (numstr[numstr.length-1] !== "0") {break;}
if (numstr[numstr.length-3] === ".") {break;}
}
The issue with your code is the condition, it processes all digits in reverse until the first non-zero character, without limit. You could keep a loop counter and not iterate more than 6 times; a for-loop with appropriate exit condition would work here. Though you don't need to make it this complicated.
Two simple methods:
1000000 to remove the last 6 digits.console.log(Math.floor(800000000 / 1000000)) // 800
console.log(Math.floor(699000000 / 1000000)) // 699console.log("800000000".slice(0, -6)) // 800
console.log("699000000".slice(0, -6)) // 699If you need a more general/unopinionated solution, use a for-loop to check each character from the end for non-zero-ness, and slice that amount, up to 6|max from the string and return.
const removeUpTo6Zeros = val => {
let i;
for (i = 0; i < 6; i++) {
if (val[val.length - 1 - i] !== '0') break;
}
return i ? val.slice(0, -i) : val;
};
console.log(removeUpTo6Zeros("800000000")); // 800
console.log(removeUpTo6Zeros("699000000")); // 699
console.log(removeUpTo6Zeros("699000030")); // 69900003
console.log(removeUpTo6Zeros("699001003")); // 699001003
console.log(removeUpTo6Zeros("69900")); // 699
console.log(removeUpTo6Zeros("69")); // 69
console.log(removeUpTo6Zeros("6")); // 6
console.log(removeUpTo6Zeros("0")); // ""
console.log(removeUpTo6Zeros("00")); // ""
console.log(removeUpTo6Zeros("000")); // ""