Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

250
Visualizações
jQuery: How to get input value within an ajax call?

I have a jQuery script, in which I need to load data from a CSV from an external URL.

At the same time, I need to combine the data from the CSV with data provided by a frontend user through an input field. My expected result would be that I'd be able to call the jQuery code for fetching the value from the user's entry into the input field. However, while this works when the code is placed outside the ajax call, it does not work inside.

At the same time, I can't place the code for fetching the user's input outside the ajax call, as I need to be able to utilize information from the loaded CSV together with the user input to perform a dynamic calculation.

My code is as below:

HTML:

<input type="text" id="my_input" value="12" maxlength="2">

Javascript:

$.ajax({
    url: csv_url,
    async: false,
    success: function (csvd) {
      var csv = $.csv.toObjects(csvd);
      // XYZ done with the CSV data to populate various fields

      $("#my_input").keyup(function () {
          console.log(this.value);
          // this does not result in anything being logged
      });
    },
    dataType: "text",
    complete: function () {}
  });
about 4 years ago · Juan Pablo Isaza
1 Respostas
Responde à pergunta

0

Of course it will not work. You are telling the compiler to add the keyup event listener to input after the ajax call is successful. Which means it will not work until ajax call is completed successfully.

You need to put the keyup event listener outside and inside the ajax call just get the value like below:

let myInputValue = "";

    $("#my_input").keyup(function () {
        console.log(this.value);
        myInputValue  = this.value;

     });
    
    $.ajax({
        url: csv_url,
        async: false,
        success: function (csvd) {
          var csv = $.csv.toObjects(csvd);
          // XYZ done with the CSV data to populate various fields
    
          //And later use the myInputValue here
        },
        dataType: "text",
        complete: function () {}
      });

You have not give us enough info. if you only need the current value in the ajax call you can do like below:

$.ajax({
            url: csv_url,
            async: false,
            success: function (csvd) {
              var csv = $.csv.toObjects(csvd);
              // XYZ done with the CSV data to populate various fields
        
              let myInputValue = $("#my_input").val();//And later use the myInputValue here
            },
            dataType: "text",
            complete: function () {}
          });
about 4 years ago · Juan Pablo Isaza Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda