I have a strings with this pattern,
ver1.1/hello/12345/bar -> extract 12345
world/098767123/foo -> extract 098767123
ver1.2344/foo/78687115/ -> extract 78687115
I used /\d+/g or /\d+/, but didn't have luck that always ver numbers come too. How can I extract numbers which does not have any char and between slashes?
Use a capturing group to capture only the numbers between slashes: \/(\d+)\/
console.log("ver1.1/hello/12345/bar".match(/\/(\d+)\//))You can use a capture group for this, e.g.:
var regex = /\/(\d+)\//;
var string = "ver1.2344/foo/78687115/";
var match = string.match(regex);
if (match) {
console.log(match[1]);
}
You can also use /(?:\/|^)(\d+)(?:\/|$)/ for numbers that happen at the beginning or end of the string. This just has two non-capturing groups that say "match / or the beginning/end"
You can add a map to the output of the match to strip out the slashes.
The use of the global flag g also prevented duplicate results.
const regEx = /(?:\/)(\d+)(?:\/)/g;
const source = "ver1.1/hello/12345/bar";
const arrResults = Array.from(source.matchAll(regEx), m => m[1]);
console.log(arrResults)