I am trying to filter object array based on user selected value from drop down list
As you see in below example I want to filter the array based on chain and officeid. If one of them is empty then I want to skip that filter.
let list = [{
"index": 4,
"chain": "aaa",
"officeId": "bbb"
},
{
"index": 5,
"chain": "ccc",
"officeId": "ddd"
}];
function search(chain, office) {
let data = list.filter(function(result) {
return result.chain === chain && result.officeId === office;
});
console.log(data);
}
search('aaa','bbb'); // this will work fine
search('aaa',''); // this returns empty array
search('', 'bbb'); // empty arrayIn above 3 statements I am expecting same output for all
If both are empty then it should skip the filter and return original array
i.e search('', ''); should not apply any filters
try using this instead, you just have to add one more condition
let list = [{
"index": 4,
"chain": "aaa",
"officeId": "bbb"
},
{
"index": 5,
"chain": "ccc",
"officeId": "ddd"
}];
function search(chain, office) {
let data = list.filter(function(result) {
if( result.chain === chain && result.officeId === office){
return result
}
if(!chain && !office){
return result;
}
});
console.log(data);
}
search('aaa','bbb'); // this will work fine
search('aaa',''); // this returns empty array
search('', 'bbb'); // empty array
search("","");
You can also use a short hand like this
let data = list.filter(function(result) {
return (!chain && !office) || (result.chain === chain && result.officeId === office);
});