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0

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clean way to handle button css attributes with jquery

I have some buttons that I make visible at the time I make my graph visible. I also put a line through the text depending on the dataset visibility status. Is there a way to pass an argument to the jquery $() so that I can handle this logix in a neat for loop?

if (!this.drawnAlready) {
        //button subscription
        $('#ds0').css("visibility", "visible");
        $('#ds0').click( function(){
            chartTest.data.datasets[0].hidden = !chartTest.data.datasets[0].hidden;
            chartTest.update();
            $('#ds0').css("text-decoration", chartTest.data.datasets[0].hidden ? "line-through" : "none");
        });
        $('#ds1').css("visibility", "visible");
        $('#ds1').click( function(){
            chartTest.data.datasets[1].hidden = !chartTest.data.datasets[1].hidden;
            chartTest.update();
            $('#ds1').css("text-decoration", chartTest.data.datasets[1].hidden ? "line-through" : "none");
        });
        $('#ds2').css("visibility", "visible");
        $('#ds2').click( function(){
            chartTest.data.datasets[2].hidden = !chartTest.data.datasets[2].hidden;
            chartTest.update();
            $('#ds1').css("text-decoration", chartTest.data.datasets[2].hidden ? "line-through" : "none");
        });
        $('#ds3').css("visibility", "visible");
        $('#ds3').click( function(){
            chartTest.data.datasets[3].hidden = !chartTest.data.datasets[3].hidden;
            chartTest.update();
            $('#ds3').css("text-decoration", chartTest.data.datasets[3].hidden ? "line-through" : "none");
        });
}

In the example I show that I do it for three buttons for code clarity, but in my code there are quite a lot of buttons so the code seems clearly improvable :).

about 4 years ago · Juan Pablo Isaza
2 Respostas
Responde à pergunta

0

Give all your #ds0/#ds1/etc the same class="ds", also give them a data-datasetid="0" to replace the #ds0 etc

<button class="ds" data-datasetid="0">toggle data set 0</button>
<button class="ds" data-datasetid="1">toggle data set 1</button>

then replace your code with:

if (!this.drawnAlready) {
    $('.ds').css("visibility", "visible");
    $('.ds').click(function() {
        var dataset = $(this).data("datasetid");
        chartTest.data.datasets[dataset].hidden = !chartTest.data.datasets[dataset].hidden;
        chartTest.update();
        $(this).css("text-decoration", chartTest.data.datasets[dataset].hidden ? "line-through" : "none");
    });
}
about 4 years ago · Juan Pablo Isaza Relatório

0

You are repeating code. So, just write a method that does the repeating part of your code.

For example:

function doThings(i)
{
  const elementId = '#ds'+i;
  $(elementId).css("visibility", "visible");
        $(elementId).click( function(){
            chartTest.data.datasets[i].hidden = !chartTest.data.datasets[i].hidden;
            chartTest.update();
            $(elementId).css("text-decoration", chartTest.data.datasets[i].hidden ? "line-through" : "none");
        });
}

Then you just need to call this function multiple times. For example:

[1, 2, 3, 4, 5].forEach( i => doThings(i))
about 4 years ago · Juan Pablo Isaza Relatório
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