my last function reducedArr, is being skipped?
when I console.log I get the newArry returned?
why is not executed??
const sumAll = function(...args) {
let newArr = [...args];
let sortedArr = newArr.sort(function(a,b) {
return a - b;
})
let lastArr = ['']
for (let i = sortedArr[0]; i < sortedArr[1]; ++i ) {
lastArr.push(i)
}
let reducedArr = lastArr.reduce(function(previousValue,currentValue) {
return previousValue + currentValue;
})
return reducedArr;
};
console.log(sumAll(1,4));
Your last reduce is still working, it just appends string instead of number because you init let lastArr = [''] with a '' item.
Update it to let lastArr = []. You will see the final result.
const sumAll = function(...args) {
let newArr = [...args];
let sortedArr = newArr.sort(function(a,b) {
return a - b;
})
let lastArr = []
for (let i = sortedArr[0]; i < sortedArr[1]; ++i ) {
lastArr.push(i)
}
console.log(lastArr);
let reducedArr = lastArr.reduce(function(previousValue,currentValue) {
return previousValue + currentValue;
})
return reducedArr;
};
console.log(sumAll(1,4));You can just write the code more succinct using Array.from and reduce
NOTE: If you want to add
1 + 2 + 3 + 4if you say as1-4then you can replaceArray.from({ length: end - start + 1 }, (_, i) => i + start)
const sumAll = function (a, b) {
const [start, end] = a > b ? [b, a] : [a, b];
return Array.from({ length: end - start }, (_, i) => i + start)
.reduce((acc, curr) => acc + curr);
};
console.log(sumAll(1, 4));
console.log(sumAll(4, 1));