I'm starting with Javascript, I am trying to make a fetch behave synchronously. I need that after calling a function that ends up calling the fecth to process the result.
async function _send_sync_command(command) {
const response = await fetch("http://localhost:5700" + "/ext", {
method: "POST",
headers: {
"Content-type": "application/json; charset=UTF-8"
},
body: JSON.stringify(command)
});
const data = await response.json();
return data;
}
function send_command(command) {
this._send_sync_command(command)
.then((data) => {
return data;
})
}
function DownloadToFP(star_cmd, next_cmd, end_cmd) {
var json_out = {};
json_out.data_0 = "";
json_out.data_1 = "";
// Start download command
var response = this.send_command(star_cmd);
// I need this to run after all promises are resolved !!!
if (response.fields.length > 0) {
json_out.data_0 = response.fields[0];
}
}
You need to await the _send_sync_command function to stop the execution of the function at this point, and return back when all promises are resolved.
Also, I don't think you need send_command function.
UPDATE
as @danh suggests to return json_out from DownloadToFP function.
async function _send_sync_command(command) {
const response = await fetch("http://localhost:5700" + "/ext", {
method: "POST",
headers: {
"Content-type": "application/json; charset=UTF-8"
},
body: JSON.stringify(command)
});
const data = await response.json();
return data;
}
async function DownloadToFP(star_cmd, next_cmd, end_cmd) {
var json_out = {};
json_out.data_0 = "";
json_out.data_1 = "";
// Start download command
var response = await this._send_sync_command(star_cmd);
// I need this to run after all promises are resolved !!!
if (response.fields.length > 0) {
json_out.data_0 = response.fields[0];
}
return json_out
}