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0

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append element that created with createElement() to elements that have specific class

I have this code and I want to append the "ul" variable to elements that have the "myselectItems" class.

my problem is here

selectedElement[i].appendChild(ul);

html code

<div class="myselectItems"></div>

javascript code

$(document).ready(function () {
let items = [
   'fab fa-500px',
   'fab fa-accessible-icon',
   'fab fa-accusoft',
   'fas fa-address-book',
],
ul = document.createElement('select');
ul.setAttribute("id", "myselect");
ul.setAttribute("name", "myselect");
ul.setAttribute("class", "myselect");
items.forEach(item => {
  let li = document.createElement('option');
   ul.appendChild(li);
      li.innerHTML += item;
 });
 const selectedElement = document.querySelectorAll('.myselectItems');
    for (var i = 0; i < selectedElement.length; i++) {
       selectedElement[i].appendChild(ul);
    }
 });
about 4 years ago · Juan Pablo Isaza
1 Respostas
Responde à pergunta

0

The issue is because you're appending the same select element each time, so that single instance gets moved between elements.

To fix this you can use cloneNode() before you append in order to create a new select instance for each div.

selectedElement[i].appendChild(ul.cloneNode(true));

Also note that you should remove the id attribute you set on the select, otherwise it will be duplicated which is invalid. id must be unique.

$(document).ready(function() {
  let items = [
    'fab fa-500px',
    'fab fa-accessible-icon',
    'fab fa-accusoft',
    'fas fa-address-book',
  ];
  var ul = document.createElement('select');
  ul.setAttribute("name", "myselect");
  ul.setAttribute("class", "myselect");
  items.forEach(item => {
    let li = document.createElement('option');
    ul.appendChild(li);
    li.innerHTML += item;
  });
  const selectedElement = document.querySelectorAll('.myselectItems');
  for (var i = 0; i < selectedElement.length; i++) {
    selectedElement[i].appendChild(ul.cloneNode(true));
  }
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<div class="myselectItems"></div>
<div class="myselectItems"></div>
<div class="myselectItems"></div>

Also note that you can simplify the code:

jQuery($ => {
  let items = ['fab fa-500px', 'fab fa-accessible-icon', 'fab fa-accusoft', 'fas fa-address-book'];
  let selectHtml = `<select name="myselect" class="myselect">${items.map(t => `<option>${t}</option>`)}</select>`;

  $('.myselectItems').append(selectHtml); // jQuery version

  //document.querySelectorAll('.myselectItems').forEach(el => el.innerHTML = selectHtml); // plain JS version  
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<div class="myselectItems"></div>
<div class="myselectItems"></div>
<div class="myselectItems"></div>

about 4 years ago · Juan Pablo Isaza Relatório
Responde à pergunta
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