Requires regex to compare last digit in string.
// For example:
const reg = RegExp("anythink...5") // expression to check that the last number is 5
reg.test("2fae71c8-a657-41b7-8d8c-3d4da10285fc") => true
reg.test("2fae71c8-fc5") => true
reg.test("2364872368745") => true
reg.test("87415B11-7143-4E5B-9B25-6117571DFEC8") => false
Please help me find a solution.
You can use
/5(?=\D*$)/
/5(?!\D*\d)/
See the JavaScript demo:
const reg = /5(?=\D*$)/
console.log(reg.test("2fae71c8-a657-41b7-8d8c-3d4da10285fc")) // => true
console.log(reg.test("2fae71c8-fc5")) //=> true
console.log(reg.test("2364872368745")) //=> true
console.log(reg.test("87415B11-7143-4E5B-9B25-6117571DFEC8"))// => falseThe 5(?=\D*$) regex matches
5 - a 5 digit char(?=\D*$) - a positive lookahead that requires zero or more non-digit chars till end of string(?!\D*\d) - a negative lookahead that fails the match if there is a digit after 5 and any zero or more non-digit chars.Use regexr.com to construct and check your Regular Expressions. You can even add multiple tests to see if it works for you in a glance.
You can match 5 optionally followed by any char except a digit or a newline using:
5[^\d\n]*$
You might also use \D* to match any char except a digit, but note that it could also match a newline.
See a regex demo.
const reg = /5[^\d\n]*$/; // expression to check that the last number is 5
console.log(reg.test("2fae71c8-a657-41b7-8d8c-3d4da10285fc")); // => true
console.log(reg.test("2fae71c8-fc5")); // => true
console.log(reg.test("2364872368745")); // => true
console.log(reg.test("87415B11-7143-4E5B-9B25-6117571DFEC8")); // => false