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0

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Javascript: How to convert a list of objects with many key-value pairs into one big nested object?

for example, from this:

const items = [
        {
            "id": 3,
            "orgId": 2,
            "mod": "toyota",
            "part": "wheel",
            "price": 333
        },
        {
            "id": 4,
            "orgId": 2,
            "mod": "toyota",
            "part": "shell",
            "price": 350
        },
        {
            "id": 9,
            "orgId": 2,
            "mod": "honda",
            "part": "wheel",
            "price": 222
        },
        {
            "id": 10,
            "orgId": 2,
            "mod": "honda",
            "part": "shell",
            "price": 250
        }
    ]


and convert to:


items = {
    "toyota": {"wheel": 333, "shell": 350 }, 
    "honda": {"wheel": 222, "shell": 250 }
}

What is the most elegant way?

I was trying to use .map() but I'm not sure how to complete the nested struture.


Follow up:

Using this method:

      const structure = {};
      prices.forEach((e) => {
       structure[e.mod] ??= {};
       structure[e.mod][e.part] = e.price;
      });

or:

      result = items.reduce((r, o) => {
        r[o.mod] ??= {};
        r[o.mod][o.part] = o.price;
        return r;
      },{});

I got the following error:

Module parse failed: Unexpected token (56:31)
File was processed with these loaders:
 * ./node_modules/@pmmmwh/react-refresh-webpack-plugin/loader/index.js
 * ./node_modules/react-scripts/node_modules/babel-loader/lib/index.js
You may need an additional loader to handle the result of these loaders.
|       const structure = {};
|       prices.forEach(e => {
>         structure[e.mod] ??= {};
|         structure[e.mod][e.part] = e.price;
|       });

I have done quite a lot searching but cannot find how to solve it.

Any advices?

about 4 years ago · Juan Pablo Isaza
3 Respostas
Responde à pergunta

0

You can use array#reduce to group based on mod.

const items = [ { "id": 3, "orgId": 2, "mod": "toyota", "part": "wheel", "price": 333 }, { "id": 4, "orgId": 2, "mod": "toyota", "part": "shell", "price": 350 }, { "id": 9, "orgId": 2, "mod": "honda", "part": "wheel", "price": 222 }, { "id": 10, "orgId": 2, "mod": "honda", "part": "shell", "price": 250 } ],
      result = items.reduce((r, o) => {
        r[o.mod] ??= {};
        r[o.mod][o.part] = o.price;
        return r;
      },{});
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

about 4 years ago · Juan Pablo Isaza Relatório

0

You could use the code below:

const transformedItems = items.reduce((acc, item) => {
  acc[item.mod] = { ...acc[item.mod], [item.part]: item.price }
  return acc
}, {})

console.log(transformedItems)
about 4 years ago · Juan Pablo Isaza Relatório

0

You could also iterate through items and populate the result object as below:

const items = [ { "id": 3, "orgId": 2, "mod": "toyota", "part": "wheel", "price": 333 }, { "id": 4, "orgId": 2, "mod": "toyota", "part": "shell", "price": 350 }, { "id": 9, "orgId": 2, "mod": "honda", "part": "wheel", "price": 222 }, { "id": 10, "orgId": 2, "mod": "honda", "part": "shell", "price": 250 } ];

const result = {};
items.forEach((e) => {
  result[e.mod] = {...result[e.mod], [e.part]: e.price};
});

console.log(result);

about 4 years ago · Juan Pablo Isaza Relatório
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