Quiero crear un punto final para descargar un video y subir este video a Youtube.
Entonces, en primer lugar, obtengo la URL del video del cuerpo de la solicitud. En segundo lugar, guardo este video en la carpeta temporal. Después de eso, subo este video al canal de YouTube y el último paso es eliminar el video temporal.
Entonces mi código se cortó así:
const videoUrl = req.body.video_url; .... .... var download = async function (url: any, dest: any, cb: any) { var file = fs.createWriteStream(dest); var request = https.get(url, function (response: any) { response.pipe(file); file.on('finish', function () { file.close(cb); }); }).on('error', function (err: any) { fs.unlink(dest); if (cb) cb(err.message); }); }; const video = await download(videoUrl, file, function () { console.log('Video Download Successfull'); ===============> 3rd console output }); .... .... var readStream = await fs.createReadStream(file); readStream.on('error', function (err: any) { }); var request: any = await Youtube.videos.insert({ resource: { snippet: { title: title , description: description } , status: { privacyStatus: "private" } } , part: "snippet,status" , media: { body: readStream } }, (err: any, data: any) => { if (err) { console.log(err.response.data.error) res.status(500).json({ status: "Fail", message: "Youtube Video Upload Failed" }) } else { try { fs.unlinkSync(file) console.log("temp video file deleted from server"); ===============> 1st console output } catch (err) { console.log("temp video file not deleted") console.error(err) } res.status(200).json({ status: "Success", message: "Youtube Video Upload Successfull" }) console.log("Video upload to youtube Successfull."); ===============> 2nd console output } });Cuando llamo a este punto final, la salida de la consola es así:
temp video file deleted from server Video upload to youtube Successfull. Video Download SuccessfullPero la salida de la consola debería ser:
Video Download Successfull Video upload to youtube Successfull. temp video file deleted from serverPor qué mi flujo es incorrecto. ¿Como puedo resolver esto?
tendrá que usar Promesas, aquí usé promesas para descargar la función de video.
const videoUrl = req.body.video_url; .... .... var download = async function (url: any, dest: any, cb: any) { return new Promise((resolve, reject) => { try { var file = fs.createWriteStream(dest); var request = https.get(url, function (response: any) { response.pipe(file); file.on('finish', function () { file.close(cb); resolve(true) }); }).on('error', function (err: any) { fs.unlink(dest); if (cb) cb(err.message); reject(false) }); }catch (e) { reject(false) } }) }; const video = await download(videoUrl, file) if (video){ console.log('download success') } .... .... var readStream = await fs.createReadStream(file); readStream.on('error', function (err: any) { }); var request: any = await Youtube.videos.insert({ resource: { snippet: { title: title , description: description } , status: { privacyStatus: "private" } } , part: "snippet,status" , media: { body: readStream } }, (err: any, data: any) => { if (err) { console.log(err.response.data.error) res.status(500).json({ status: "Fail", message: "Youtube Video Upload Failed" }) } else { try { fs.unlinkSync(file) console.log("temp video file deleted from server"); ===============> 1st console output } catch (err) { console.log("temp video file not deleted") console.error(err) } res.status(200).json({ status: "Success", message: "Youtube Video Upload Successfull" }) console.log("Video upload to youtube Successfull."); ===============> 2nd console output } });