What would be the best way of filtering out an object in an array based on 2 factors, I thought a simple && operator would work but I was mistaken.
{
email: 'email@email.com',
accounts: [
{ name: 'Bob', country: 'UK' },
{ name: 'Chris', country: 'USA' },
{ name: 'Bob', country: 'USA' },
]
}
My original filter would just filter out based on accounts.name != 'Bob' however this can be problematic as there could be 2 Bobs with different countries.
let filterOut = result.accounts.filter(function (element) {
return element.name != 'Bob' && element.country != 'UK';
});
How could I use filter (if that is even the best option here) to achive the below output:
[
{ name: 'Chris', country: 'USA' },
{ name: 'Bob', country: 'USA' },
]
You could use an OR (||) to filter
data.accounts.filter(f => f.name != "Bob" || f.country == 'USA');
let data = {
email: 'email@email.com',
accounts: [
{ name: 'Bob', country: 'UK' },
{ name: 'Chris', country: 'USA' },
{ name: 'Bob', country: 'USA' },
]
}
let filtered = data.accounts.filter(f => f.name != "Bob" || f.country == 'USA');
console.log(filtered)You are filtering out every value that is both not 'Bob' and not 'UK'.
Here are two possible solutions. The right answer probably depends on exactly what it means to filter "based on 2 factors".
const input = {
email: 'email@email.com',
accounts: [
{ name: 'Bob', country: 'UK' },
{ name: 'Chris', country: 'USA' },
{ name: 'Bob', country: 'USA' },
],
};
// Filter out every value with either name 'Bob' or country 'UK'.
const outputV1 = input.accounts.filter(v => v.name !== 'Bob' || v.country !== 'UK');
console.log(outputV1);
// Filter out every value with name 'Bob' and country 'UK'.
const outputV2 = input.accounts.filter(v => `${v.name}-${v.country}` !== 'Bob-UK');
console.log(outputV2);