Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

148
Visualizações
How to find unique value with id in JavaScript?

How to find unique value with id in JavaScript? right now I'm getting just value.

I'm getting:-

[
  "Care One",
  "Care Two"
]

I need:-

[
{
    "Source_ID": 1,
    "SourceName_CR": "Care One"
},
{
    "Source_ID": 2,
    "SourceName_CR": "Care Two"
}

]

My code:-

const body = [
{
            Field_ID: 1,
            FieldName_CR: "First Name",
            Source_ID: 1,
            SourceName_CR: "Care One"
        },
        {
            Field_ID: 2,
            FieldName_CR: "Last Name",
            Source_ID: 1,
            SourceName_CR: "Care One"
        }, {
            Field_ID: 3,
            FieldName_CR: "Phone",
            Source_ID: 2,
            SourceName_CR: "Care Two"
        },
        {
            Field_ID: 4,
            FieldName_CR: "Email",
            Source_ID: 2,
            SourceName_CR: "Care Two"
        },  ];

console.log([...new Set(body.map(item => item.SourceName_CR))]);

almost 4 years ago · Santiago Trujillo
3 Respostas
Responde à pergunta

0

A Set won't work here because you want to deduplicate objects - but objects can't be compared with each other that way. Doing just .map(item => item.SourceName_CR) doesn't make sense either because then you only get the string (eg Care Two) and not the whole object you want.

Group the source names by the source IDs to deduplicate, then turn the entries of the resulting object into the required structure.

const body = [
{
    Field_ID: 1,
    FieldName_CR: "First Name",
    Source_ID: 1,
    SourceName_CR: "Care One"
},
{
    Field_ID: 2,
    FieldName_CR: "Last Name",
    Source_ID: 1,
    SourceName_CR: "Care One"
}, {
    Field_ID: 3,
    FieldName_CR: "Phone",
    Source_ID: 2,
    SourceName_CR: "Care Two"
},
{
    Field_ID: 4,
    FieldName_CR: "Email",
    Source_ID: 2,
    SourceName_CR: "Care Two"
},  ];
const namesBySourceID = Object.fromEntries(
  body.map(obj => [obj.Source_ID, obj.SourceName_CR])
);
const result = Object.entries(namesBySourceID)
  .map(([Source_ID, SourceName_CR]) => ({ Source_ID, SourceName_CR }));
console.log(result);

almost 4 years ago · Santiago Trujillo Relatório

0

This would also work:

const body = [ { Field_ID: 1, FieldName_CR: "First Name", Source_ID: 1, SourceName_CR: "Care One", }, { Field_ID: 2, FieldName_CR: "Last Name", Source_ID: 1, SourceName_CR: "Care One", }, { Field_ID: 3, FieldName_CR: "Phone", Source_ID: 2, SourceName_CR: "Care Two", }, { Field_ID: 4, FieldName_CR: "Email", Source_ID: 2, SourceName_CR: "Care Two", }, ];

const uniqueItems = [];

body.forEach(({Source_ID, SourceName_CR}) => {
    const found = uniqueItems.find(o => o.Source_ID === Source_ID);
    if(!found){
        uniqueItems.push({Source_ID, SourceName_CR});
    }
})

console.log(uniqueItems);

almost 4 years ago · Santiago Trujillo Relatório

0

const body = [
{
            Field_ID: 1,
            FieldName_CR: "First Name",
            Source_ID: 1,
            SourceName_CR: "Care One"
        },
        {
            Field_ID: 2,
            FieldName_CR: "Last Name",
            Source_ID: 1,
            SourceName_CR: "Care One"
        }, {
            Field_ID: 3,
            FieldName_CR: "Phone",
            Source_ID: 2,
            SourceName_CR: "Care Two"
        },
        {
            Field_ID: 4,
            FieldName_CR: "Email",
            Source_ID: 2,
            SourceName_CR: "Care Two"
        },  ];
        
const key = 'SourceName_CR';

const uniqValues = [...new Map(body.map(item =>[item[key], item])).values()];

const onlyIDandNames=uniqValues.map((item)=>({Source_ID:item?.Source_ID,SourceName_CR:item?.SourceName_CR}))

console.log(uniqValues)
console.log(onlyIDandNames)

almost 4 years ago · Santiago Trujillo Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda