Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

374
Visualizações
Javascript sort array of objects using array of priority

I have this array of objects:

var eventList = [
    {
        eventName: "abc",
        status: "completed"
    },
    {
        eventName: "def",
        status: "live"
    },
    {
        eventName: "ghi",
        status: "live"
    },
    {
        eventName: "jkl",
        status: "upcoming"
    },
]

I want to sort these array of objects using a priority array of a specific key, say ["live", "upcoming", "completed"] for status, meaning all live events come first, followed by upcoming followed by completed. Answers all over the internet seem like you can only sort array objects using keys as ascending or descending. How to I approach this?

over 4 years ago · Santiago Trujillo
2 Respostas
Responde à pergunta

0

You could do it using Array.prototype.sort() method with an ordering array.

const eventList = [
  {
    eventName: 'abc',
    status: 'completed',
  },
  {
    eventName: 'def',
    status: 'live',
  },
  {
    eventName: 'ghi',
    status: 'live',
  },
  {
    eventName: 'jkl',
    status: 'upcoming',
  },
];

const order = ['live', 'upcoming', 'completed'];
eventList.sort((x, y) => order.indexOf(x.status) - order.indexOf(y.status));
console.log(eventList);

If you would want to make index searching faster when sorting you could use Map Object.

const eventList = [
  {
    eventName: 'abc',
    status: 'completed',
  },
  {
    eventName: 'def',
    status: 'live',
  },
  {
    eventName: 'ghi',
    status: 'live',
  },
  {
    eventName: 'jkl',
    status: 'upcoming',
  },
];

const order = ['live', 'upcoming', 'completed'];
const map = new Map();
order.forEach((x, i) => map.set(x, i));
eventList.sort((x, y) => map.get(x.status) - map.get(y.status));
console.log(eventList);

over 4 years ago · Santiago Trujillo Relatório

0

You can do this without sorting for a linear time complexity by first grouping your array based on status, and then using .flatMap() on your order array. For each value in the ordered array, you can grab the grouped value from the grouping in O(1) (ie: instantly), and map those grouped objects. As you're using flatMap these grouped objects will be flattened into the resulting array:

const eventList = [ { eventName: "abc", status: "completed" }, { eventName: "def", status: "live" }, { eventName: "ghi", status: "live" }, { eventName: "jkl", status: "upcoming" }, ];

const order = ["live", "upcoming", "completed"];
const grouped = eventList.reduce(
  (map, o) => map.set(o.status, (map.get(o.status) || []).concat(o)), new Map
);

const result = order.flatMap(status => grouped.get(status) || []);
console.log(result);

over 4 years ago · Santiago Trujillo Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda