I have a String:
String thestra = "/aaa/bbb/ccc/ddd/eee";
Every time, in my situation, for this Sting, a minimum of two slashes will be present without fail.
And I am getting the /aaa/ like below, which is the subString between "FIRST TWO occurrences" of the char / in the String.
System.out.println("/" + thestra.split("\\/")[1] + "/");
It solves my purpose but I am wondering if there is any other elegant and cleaner alternative to this?
Please notice that I need both slashes (leading and trailing) around aaa. i.e. /aaa/
You can use indexOf, which accepts a second argument for an index to start searching from:
int start = thestra.indexOf("/");
int end = thestra.indexOf("/", start + 1) + 1;
System.out.println(thestra.substring(start, end));
Whether or not it's more elegant is a matter of opinion, but at least it doesn't find every / in the string or create an unnecessary array.
Scanner::findInLine returning the first match of the pattern may be used:
String thestra = "/aaa/bbb/ccc/ddd/eee";
System.out.println(new Scanner(thestra).findInLine("/[^/]*/"));
Output:
/aaa/
Use Pattern and Matcher from java.util.regex.
Pattern pattern = Pattern.compile("/.*?/");
Matcher matcher = pattern.matcher(str);
if (matcher.find()) {
String match = matcher.group(0); // output
}