I'm doing a linux online course but im stuck with a question, you can find the question below.
You will get three files called a.bf, b.bf and c.bf. Merge the contents of these three files and write it to a new file called abc.bf. Respect the order: abc.bf must contain the contents of a.bf first, followed by those of b.bf, followed by those of c.bf.
Example Suppose the given files have the following contents:
a.bf contains +++.
b.bf contains [][][][].
c.bf contains <><><>.
The file abc.bf should then have
+++[][][][]<><><>
as its content. I know how to merge the 3 files but when i use cat my output is:
+++
[][][]
<><><>
When i use paste my output is "+++ 'a lot of spaces' [][][][] 'a lot of spaces' <><><>"
My output that i need is +++[][][][]<><><>, i dont want the spaces between the content. Can someone help me?
echo -n "$(cat a.bf)$(cat b.bf)$(cat c.bf)" > abc.bf
-n will not output trailing newlinesWhat you want to do is delete the newline characters.
With tr:
cat {a,b,c}.bf | tr --delete '\n' > abc.bf
With echo & sed:
echo $(cat {a,b,c}.bf) | sed -E 's/ //g' > abc.bf
With xargs & sed:
<{a,b,c}.bf xargs | sed -E 's/ //g' > abc.bf
Note that sed is only used to remove the spaces.
With cat & sed:
cat {a,b,c}.bf | sed -z 's/\n//g'