Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

134
Visualizações
Where is array's length property defined?

We can determine the length of an ArrayList<E> using its public method size(), like

ArrayList<Integer> arr = new ArrayList(10);
int size = arr.size();

Similarly we can determine the length of an Array object using the length property

String[] str = new String[10];
int size =  str.length;

Whereas the size() method of ArrayList is defined inside the ArrayList class, where is this length property of Array defined?

over 4 years ago · Santiago Trujillo
3 Respostas
Responde à pergunta

0

Arrays are special objects in java, they have a simple attribute named length which is final.

There is no "class definition" of an array (you can't find it in any .class file), they're a part of the language itself.

10.7. Array Members

The members of an array type are all of the following:

  • The public final field length, which contains the number of components of the array. length may be positive or zero.
  • The public method clone, which overrides the method of the same name in class Object and throws no checked exceptions. The return type of the clone method of an array type T[] is T[].

    A clone of a multidimensional array is shallow, which is to say that it creates only a single new array. Subarrays are shared.

  • All the members inherited from class Object; the only method of Object that is not inherited is its clone method.

Resources:

  • JLS - Arrays
over 4 years ago · Santiago Trujillo Relatório

0

It's "special" basically, with its own bytecode instruction: arraylength. So this method:

public static void main(String[] args) {
    int x = args.length;
}

is compiled into bytecode like this:

public static void main(java.lang.String[]);
  Code:
   0:   aload_0
   1:   arraylength
   2:   istore_1
   3:   return

So it's not accessed as if it were a normal field. Indeed, if you try to get it as if it were a normal field, like this, it fails:

// Fails...
Field field = args.getClass().getField("length");
System.out.println(field.get(args));

So unfortunately, the JLS description of each array type having a public final field length is somewhat misleading :(

over 4 years ago · Santiago Trujillo Relatório

0

It's defined in the Java language specification:

The members of an array type are all of the following:

  • The public final field length, which contains the number of components of the array. length may be positive or zero.

Since there is a limitless number of array types (for every class there is a corresponding array type, and then there are multidimensional arrays), they cannot be implemented in a class file; the JVM has to do it on the fly.

over 4 years ago · Santiago Trujillo Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda