To copy a file and save it to its destination path, you can use the method below.

 public static void copy(File src, File dst) throws IOException { InputStream in = new FileInputStream(src); try { OutputStream out = new FileOutputStream(dst); try { // Transfer bytes from in to out byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } } finally { out.close(); } } finally { in.close(); } }

In API 19+ you can use Java's automatic resource management:

 public static void copy(File src, File dst) throws IOException { try (InputStream in = new FileInputStream(src)) { try (OutputStream out = new FileOutputStream(dst)) { // Transfer bytes from in to out byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } } } }

Alternatively you can use FileChannel to copy a file. May be faster than the byte copy method when copying a large file. However, you cannot use it if your file is larger than 2 GB.

 public void copy(File src, File dst) throws IOException { FileInputStream inStream = new FileInputStream(src); FileOutputStream outStream = new FileOutputStream(dst); FileChannel inChannel = inStream.getChannel(); FileChannel outChannel = outStream.getChannel(); inChannel.transferTo(0, inChannel.size(), outChannel); inStream.close(); outStream.close(); }

Kotlin extension for it

fun File.copyTo(file: File) {
    inputStream().use { input ->
        file.outputStream().use { output ->
            input.copyTo(output)
        }
    }
}