I want to use the following code, but without indexing the array with"[][]" and substitute it with pointers
for (int i = 0; i < argc; i++) {
for (int j = 0; argv[i][j] != '\0'; j++) {
//code
}
}
I know that you can use pointers to traverse an array, but I'm unsure how to do that with an undefined length in the second array, in this case the string from input. Since each element of argv[] can have a different length, I want to make sure that I can properly read the characters and know when each element of argv[] ends, and the next begins.
I expect it to be something like: (If the following header to main is wrong, please tell me.)
int main(int argc, char **argv) {
for (int i = 0; i < argc; i++) {
while(argv != '\0') {
//code
*argv+1;
}
//to skip null character
argv+1;
}
}
Given that the last element in argv is NULL, you don't need to index it or compare anything with argc if you really don't want to.
int main(int argc, char *argv[]) {
for (char **arg = argv; *arg; ++arg) { // for each arg
for (char *p = *arg; *p; ++p) { // for each character
process(*p);
}
}
}
*arg will be NULL at the end of the list of arguments, which is false. *p will be '\0' at the end of each string, which is false.
From N1256 5.1.2.2.1/2
If they are declared, the parameters to the main function shall obey the following constraints:
— The value of argc shall be nonnegative.
— argv[argc] shall be a null pointer.
Since for loop allows any kind of values, not necessarily integers for your "loop index", your loop could be rewritten like this:
for (char **a = argv ; a != argv+argc ; a++) {
for(char *p = *a ; *p != '\0' ; p++) {
// code uses *p instead of argv[i][j]
}
}
The inner loop uses p as the loop variable, which is incremented with the regular p++, and checked with *p != '\0'. The loop condition could be shortened to *p, so the inner loop would look like this:
for(char *p = *a ; *p ; p++)
Yes you can iterate through argv using pointers.
The inner loop tells p to point at the beginning of argv+i and iterate through it until it reaches \0.
#include <stdio.h>
int main(int argc, char **argv) {
int i;
char *p;
for(i=0; i < argc; i++) {
for(p=*(argv+i); *p; p++)
printf("%c", *p);
printf("\n");
}
}
If you are only interested in traversing the each arguments, but not interested in parsing each character, then you can simply.
#include <stdio.h>
int main(int argc, char **argv) {
int i;
char *p;
for(i=0; i < argc; i++) {
printf("Argument position %d is %s\n", i, *(argv+i));
}
}