Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

194
Visualizações
Why there shall be no more than one read access with volatile-qualified type within one sequence point?

Given the following code:

static volatile float32_t tst_mtr_dutycycle;
static volatile uint8_t tst_mtr_direction;
static volatile uint32_t tst_mtr_update;

void TST_MTR_Task(void)
{
    if (tst_mtr_update == 1U)
    {
        tst_mtr_update = 0;

        MTR_SetDC(tst_mtr_dutycycle, tst_mtr_direction);
    }
}

I found problems with MISRA C 2012 Rule-13.2 and I decided to make some research. I found here (http://archive.redlizards.com/docs/misrac2012-datasheet.pdf) that:

there shall be no more than one read access with volatile-qualified type within one sequence point

The thing here is that I haven't been able to find an example or explanation that makes clear why there shall be no more than one read access with volatile-qualified type within one sequence point.

I need to find a solution for the violating code but is not really clear to me what to do.

I know now that there shall be no more than one read access with volatile-qualified type within one sequence point. The question is, why? and I need to know why in order to implement a solution and to explain everybody here why I am changing the code.

Regards.

over 4 years ago · Santiago Trujillo
2 Respostas
Responde à pergunta

0

The justification for the rule is:

(Required) The value of an expression and its persistent side effects shall be the same under all permitted evaluation orders

If more than one volatile-qualified variable is read between sequence points, then it is unspecified which is read first. Reading a volatile variable is a side effect.

The solution is to explicitly order the reads:

void TST_MTR_Task(void)
{
    if (tst_mtr_update == 1U)
    {
        tst_mtr_update = 0;

        float32_t dutycycle = tst_mtr_dutycycle;
        uint8_t direction = tst_mtr_direction;
        MTR_SetDC(dutycycle, direction);
    }
}
over 4 years ago · Santiago Trujillo Relatório

0

There are no sequence points between fetching the arguments of a function call. So the order they are fetched is undefined by the standard. OTOH, the compiler has to maintain the order of accesses to volatile objects, so this is a contradiction.

Fetch the variables to non-volatile temps and use those for the function call:

float32_t t1 = tst_mtr_dutycycle;
uint8_t t2 = tst_mtr_direction;
MTR_SetDC(t1, t2);

Note this is actually an issue for standard C and not just related to MISRA-compliance.

As you appear to have multiple problems regarding standard compliance, you might want to keep the standard under your pillow.

over 4 years ago · Santiago Trujillo Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda