I have these five source
main.c
src_print1.c
src_print2.c
header_print1.h
header_print2.h
the contents are simple and are as following for respective files:
main.c
#include "header_print1.h"
#include "header_print2.h"
int main(int argc, char** argv) {
print1();
print2();
return 0;
}
header_print1.h
#ifndef PRINT_1
#define PRINT_1
#include <stdio.h>
#include <stdlib.h>
void print1();
#endif
header_print2.h
#ifndef PRINT_2
#define PRINT_2
#include <stdio.h>
#include <stdlib.h>
void print2();
#endif
src_print1.c
#include "header_print1.h"
void print1() {
printf("Hello 1\n");
}
src_print2.c
#include "header_print2.h"
void print2() {
printf("Hello 2\n");
}
Using gcc I have tried to compile using the following command line:
gcc -I ./ -o test -c main.c src_print1.c src_print2.c
Everything is in the same folder. The error I get is:
gcc: cannot specify -o with -c or -S with multiple files
I looked up at gcc manual, but actually I don't understand what to do in this case, since usually I use IDE and not the command line.
IMHO, if you rewrite your compilation statement like
gcc -I./ -o test main.c src_print1.c src_print2.c
You'll be good to go. There is no need for -c flag [NOTE] when you're specifying the output binary using -o.
Also, as mentioned here, all the files are in same directory, you can even shorten the statement as
gcc -o test main.c src_print1.c src_print2.c
Suggestion: While the above change(s) will do the job, this is not considered an elegant way of doing so. Please consider creating a makefile which will make your life easier.
[Note]:
Regarding the -c option, as per the online gcc manual, (emphasis mine)
-c
Compile or assemble the source files, but do not link. The linking stage simply is not done. The ultimate output is in the form of an object file for each source file.
So, it should be clear by now, why you got the error.