I'm trying to check if pointer is pointing at some char.
Like this:
#include<stdio.h>
#include<string.h>
#define a 3
int func(char *);
int main()
{
char *s="a";
int type;
type=func(s);
printf("%d",type);
return 0;
}
int func(char *s)
{
int type;
if(*s=="a")
{
type=1;
}
return type;
}
But I constantly get warning: warning: comparison between pointer and integer if(*s=="a")
Is it possible to compare pointer and integers?
Is there another way to resolve this problem?
Can I find out at which letter is pointing *s without printing it?
"a" is not a character, it is a string literal. 'a' is a character literal, which is what you are looking for here.
Also note that in your comparison *s == "a" it is actually the "a" which is the pointer, and *s which is the integer... The * dereferences s, which results in the char (an integer) stored at the address pointed to by s. The string literal, however, acts as a pointer to the first character of the string "a".
Furthermore, if you fix the comparison by changing it to *s == 'a', you are only checking whether the first character of s is 'a'. If you wish to compare strings, see strcmp.
chars are enclosed in '' not ""
#include<stdio.h>
#include<string.h>
#define a 3
int func(char *);
int main()
{
char value = 'a';
char *s=&value;
int type;
type=func(s);
printf("%d",type);
return 0;
}
int func(char *s)
{
int type;
if(*s=='a') //or if(*s==3)
{
type=1;
}
return type;
}