I've worked on this for about an hour now and I can't figure anything out that works so sorry if this is obvious.
I want my query to only return results where every result matches, but right now it returns a result if at least one match is found.
My document looks like this...
{
country: 'Great Britain',
data: [
{
school: 'King Alberts',
staff: [
{
name: 'John',
age: 37,
position: 'Head Teacher'
},
{
name: 'Grace',
age: 63,
position: 'Retired'
},
{
name: 'Bob',
age: 25,
position: 'Receptionist'
}
]
},
{
school: 'St Johns',
staff: [
{
name: 'Alex',
age: 22,
position: 'Head of Drama'
},
{
name: 'Grace',
age: 51,
position: 'English Teacher'
},
{
name: 'Jack',
age: 33,
position: 'Receptionist'
}
]
},
// ... more schools
]
}
The query I'm currently making looks like...
{ 'data.staff.name': { $in: names } }
and the 'names' array that is being provided looks like ['Bob', 'Grace', 'John', 'Will', 'Tom']. Currently both schools are being returned when I make this query, I think it's because the 'names' array contains 'Grace' which is a name present at both schools and so the document it matching. Does anyone know if there's a query I could make so mongodb only returns the school object if every name in the 'names' array is a member of staff at the school?
You need to use the aggregation pipeline for this, after matching the document we'll just filter out the none matching arrays, like so:
db.collection.aggregate([
{
$match: {
"data.staff.name": {
$in: names
}
}
},
{
$addFields: {
data: {
$filter: {
input: "$data",
cond: {
$eq: [
{
$size: {
"$setIntersection": [
"$$this.staff.name",
names
]
}
},
{
$size: "$$this.staff"
}
]
}
}
}
}
}
])