I am trying to add multiple lists into a dictionary - one key and one value list. I can do two lists to a dictionary but I am wondering how to do multiple lists joining with some missing value in one of the lists.
a = ['apple', 'orange', 'lemon']
b = ['London', 'New York', 'Tokyo']
c = ['Red', 'Orange', 'Yellow']
d = ['good', 'bad', '']
fruito = zip(a, b)
fruit_dictionary = dict(fruito); fruit_dictionary
Expected output:
fruit_dictionary = {'apple': ['London', 'Red', 'good'],
'orange': ['New York', 'Orange', 'bad'],
'lemon': ['Tokyo', 'Yellow']}
You can use the following dictionary comprehension with zip and argument packing:
{k:v for k, *v in zip(a,b,c,d)}
output:
{'apple': ['London', 'Red', 'good'],
'orange': ['New York', 'Orange', 'bad'],
'lemon': ['Tokyo', 'Yellow', '']}
Or to get rid of empty strings:
{k:[e for e in v if e] # using truthy values here, could also use e != ''
for k, *v in zip(a,b,c,d)}
output:
{'apple': ['London', 'Red', 'good'],
'orange': ['New York', 'Orange', 'bad'],
'lemon': ['Tokyo', 'Yellow']}
For completeness, I am adding here a generic solution in case the input lists have different lengths. The solution would be to use itertools.zip_longest:
a = ['apple', 'orange', 'lemon']
b = ['London', 'New York', 'Tokyo']
c = ['Red', 'Orange', 'Yellow']
d = ['good', 'bad']
from itertools import zip_longest
{k:[e for e in v if e] for k, *v in zip_longest(a,b,c,d)}