0
260
VisualizaçõesNeed to satisfy Swift protocol requirement by using a specific subclass of the requirement (or type that conforms to it)
I have a protocol that I've created (in Swift 4.2), and one of its requirements is a property that is of the same type as the protocol itself.
As an example, I have a protocol defined like so:
protocol A {
var a: A? { get set }
}
I have several Models that conform to this protocol:
class Model1: A {
var a: A?
}
class Model2: A {
var a: A?
}
For one of my models, I need to satisfy the protocol requirement by being more specific for the property defined by variable a (i.e. the variable with the protocol type). So for example I may want to implement Model2 as:
class Model2: A {
var a: Model1?
}
In this case since Model1 conforms to the protocol A you would expect this to be able to satisfy the protocol requirement, however I get an error instead:
Type 'Model2' does not conform to protocol 'A'
Why is this happening, and what can I do to make it work as described above?
Appendix
I've modelled the above scenario in an Xcode Playground and here is a screenshot of the error I'm seeing.
2 Respostas
Responde à pergunta0
To conform to protocol A, Model2 would need a member var a that allows storing a reference to anything conforming to protocol A, not just a reference to a Model1. So you can't do this.
0
You could do this with associated types:
protocol A {
associatedtype B: A
var a: B? { get }
}
This would let you declare Model2 with the specificity you wish:
class Model2: A {
var a: Model1?
}
But unfortunately, that would mean you could no longer declare variables of type A. To fix that, you could use generic models:
class Model1<T: A>: A {
var a: T?
}