I have a declarative base class News:
class News(Base):
__tablename__ = "news"
id = Column(Integer, primary_key = True)
title = Column(String)
author = Column(String)
url = Column(String)
comments = Column(Integer)
points = Column(Integer)
label = Column(String)
I also have a function f(title), that gets a string and returns one of 3 variants of strings: 'good', 'maybe' or 'never'.
I try to get filtered rows:
rows = s.query(News).filter(News.label == None and f(News.title) == 'good').all()
But the program fails, raising this error:
raise TypeError("Boolean value of this clause is not defined")
How can I resolve it?
The problem is this:
News.label == None and f(News.title) == 'good'
# ^^^ here
Python does not allow overriding the behaviour of boolean operations and and or. You can influence them to some extent with __bool__ in Python 3 and __nonzero__ in Python 2, but all that does is that it defines the truth value of your object.
If the objects in question had not implemented __bool__ and thrown the error, or the implementation had not thrown, you would've gotten possibly rather cryptic errors due to the short-circuiting nature of and and or:
In [19]: (News.label == 'asdf') and True
Out[19]: <sqlalchemy.sql.elements.BinaryExpression object at 0x7f62c416fa58>
In [24]: (News.label == 'asdf') or True
Out[24]: True
because
In [26]: bool(News.label == 'asdf')
Out[26]: False
This could and would lead to hair pulling in the form of incorrect SQL expressions:
In [28]: print(News.label == 'asdf' or News.author == 'NOT WHAT YOU EXPECTED')
news.author = :author_1
To produce boolean SQL expressions either use the and_(), or_(), and not_() sql expression functions, or the binary &, |, and ~ operator overloads:
# Parentheses required due to operator precedence
filter((News.label == None) & (f(News.title) == 'good'))
or
filter(and_(News.label == None, f(News.title) == 'good'))
or pass multiple criterion to a call to Query.filter():
filter(News.label == None, f(News.title) == 'good')
or combine multiple calls to filter():
filter(News.label == None).filter(f(News.title) == 'good')