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What is the alternative of numpy.newaxis in tensorflow?

Hi I am new to tensorflow. I want to implement the following python code in tensorflow.

import numpy as np
a = np.array([1,2,3,4,5,6,7,9,0])
print(a) ## [1 2 3 4 5 6 7 9 0]
print(a.shape) ## (9,)
b = a[:, np.newaxis] ### want to write this in tensorflow.
print(b.shape) ## (9,1)
over 4 years ago · Santiago Trujillo
3 Respostas
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0

The corresponding command is tf.newaxis (or None, as in numpy). It does not have an entry on its own in tensorflow's documentation, but is briefly mentioned on the doc page of tf.stride_slice.

x = tf.ones((10,10,10))
y = x[:, tf.newaxis] # or y = x [:, None]
print(y.shape)
# prints (10, 1, 10, 10)

Using tf.expand_dims is fine too but, as stated in the link above,

Those interfaces are much more friendly, and highly recommended.

over 4 years ago · Santiago Trujillo Relatório

0

I think that would be tf.expand_dims -

tf.expand_dims(a, 1) # Or tf.expand_dims(a, -1)

Basically, we list the axis ID where this new axis is to be inserted and the trailing axes/dims are pushed-back.

From the linked docs, here's few examples of expanding dimensions -

# 't' is a tensor of shape [2]
shape(expand_dims(t, 0)) ==> [1, 2]
shape(expand_dims(t, 1)) ==> [2, 1]
shape(expand_dims(t, -1)) ==> [2, 1]

# 't2' is a tensor of shape [2, 3, 5]
shape(expand_dims(t2, 0)) ==> [1, 2, 3, 5]
shape(expand_dims(t2, 2)) ==> [2, 3, 1, 5]
shape(expand_dims(t2, 3)) ==> [2, 3, 5, 1]
over 4 years ago · Santiago Trujillo Relatório

0

a = a[..., tf.newaxis].astype("float32")

This Works as well

over 4 years ago · Santiago Trujillo Relatório
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