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I have list of strings with separators A and B:

L = ['sgfgfqds A aaa','sderas B ffff','eeee','sdsdfd A rrr']

and need:

L1 = [['aaa'], ['ffff'], ['eeee'], ['rrr']]

I tried using:

L1 = [re.findall(r'(?<=A)(.*)$', inputtext) for inputtext in L]
print (L1)

but, it returns the following:

[[' aaa'], [], [], [' rrr']]

How can I get the desired output?

over 4 years ago · Santiago Trujillo

Alternative suggestion without regex.

[[i] for i in ' '.join(L).split(' ') if i.count(i[0]) == len(i) and len(i) > 1]

Result

 [['aaa'], ['ffff'], ['eeee'], ['rrr']]

over 4 years ago · Santiago Trujillo Relatório

You can use the fact that split returns a list even if it doesn't find the separator.

 L1 = [[x.split(' A ')[-1].split(' B ')[-1]] for x in L]

over 4 years ago · Santiago Trujillo Relatório

Responde à pergunta

Accepted Answer · 2022-05-27T14:33:48.099Z

You can use re.split to break your strings on either 'A' or 'B':

>>> L1 = [re.split(r'[AB] *', inputtext)[-1] for inputtext in L]
>>> L1
['aaa', 'ffff', 'eeee', 'rrr']