I want to exclude for example email and address using populate() function from mongodb, just get the name from it:
Example:
const results = await Seller.aggregate(aggregatePipeline).exec();
const sellers = await Seller.populate(results, { path: "user" });
When populating the user instead of having:
...
user: {
email: "hgjh@gmail.com",
address:{},
name: "name"
}
I want to only have (exclude certain data from the path):
...
user: {
name: "name"
}
You can do either,
const sellers = await Seller.populate(results, { path: "user", select: '-
email -address' });
or
const sellers = await Seller.populate(results, { path: "user", select:
'name' });
As i understand mongoose documentation https://mongoosejs.com/docs/populate.html, populate as $lookup is use to resolve a relation with other collection.
MongoDB has the join-like $lookup aggregation operator in versions >= 3.2. Mongoose has a more powerful alternative called populate(), which lets you reference documents in other collections.
In your case, you don't need to resolve a field with an other collection. You already have the final data you target . You could use $project at the end of your pipeline aggregation to keep only name field, like :
{ $project: { name:1 } }
Let me know if i helped you.
Edit :
I read too fast, if you have this data res after the populate and not after the aggreg, you may select your final field, like is said
here https://stackoverflow.com/a/72481338/16205278
user: {
email: "hgjh@gmail.com",
address:{},
name: "name"
}