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Java - Stream - Collect every N elements

I am trying to learn java - stream. I am able to do simple iteration / filter / map / collection etc.

When I was kind of trying to collect every 3 elements and print as shown here in this example, [collect every 3 elements and print and so on...]

    List<String> list = Arrays.asList("a","b","c","d","e","f","g","h","i","j");

    int count=0;
    String append="";
    for(String l: list){
        if(count>2){
            System.out.println(append);
            System.out.println("-------------------");
            append="";
            count=0;
        }
        append = append + l;
        count++;
    }
    System.out.println(append);

output:

abc
-------------------
def
-------------------
ghi
-------------------
j

I am not getting any clue how to do this using stream. Should i implement my own collector to achieve this?

about 4 years ago · Santiago Trujillo
3 Respostas
Responde à pergunta

0

You can actually use an IntStream to simulate your list's pagination.

List<String> list = Arrays.asList("a","b","c","d","e","f","g","h","i","j");

int pageSize = 3;

IntStream.range(0, (list.size() + pageSize - 1) / pageSize)
        .mapToObj(i -> list.subList(i * pageSize, Math.min(pageSize * (i + 1), list.size())))
        .forEach(System.out::println);

which outputs:

[a, b, c]
[d, e, f]
[g, h, i]
[j]

If you want to generate Strings, you can use String.join since you are dealing with a List<String> directly:

.mapToObj(i -> String.join("", list.subList(i * pageSize, Math.min(pageSize * (i + 1), list.size()))))
about 4 years ago · Santiago Trujillo Relatório

0

If you have Guava in your project, you can use Iterables.partition method:

import com.google.common.collect.Iterables;
import com.google.common.collect.Streams;
...

Stream<List<String>> stream = Streams.stream(Iterables.partition(list, 3));
about 4 years ago · Santiago Trujillo Relatório

0

You can create your own Collector. The easiest way is to call Collector.of().

Since your use case requires values to be processed in order, here is an implementation that simply doesn't support parallel processing.

public static Collector<String, List<List<String>>, List<List<String>>> blockCollector(int blockSize) {
    return Collector.of(
            ArrayList<List<String>>::new,
            (list, value) -> {
                List<String> block = (list.isEmpty() ? null : list.get(list.size() - 1));
                if (block == null || block.size() == blockSize)
                    list.add(block = new ArrayList<>(blockSize));
                block.add(value);
            },
            (r1, r2) -> { throw new UnsupportedOperationException("Parallel processing not supported"); }
    );
}

Test

List<String> input = Arrays.asList("a","b","c","d","e","f","g","h","i","j");
List<List<String>> output = input.stream().collect(blockCollector(3));
output.forEach(System.out::println);

Output

[a, b, c]
[d, e, f]
[g, h, i]
[j]
about 4 years ago · Santiago Trujillo Relatório
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