Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

376
Visualizações
Angular 2 fakeAsync waiting for timeout in a function using tick()?

I'm trying to get the results from a mock backend in Angular 2 for unit testing. Currently, we are using fakeAsync with a timeout to simulate the passing of time.

current working unit test

it('timeout (fakeAsync/tick)', fakeAsync(() => {
    counter.getTimeout();
    tick(3000); //manually specify the waiting time
}));

But, this means that we are limited to a manually defined timeout. Not when the async task is completed. What I'm trying to do is getting tick() to wait until the task is completed before continuing with the test.

This does not seem to work as intended.

Reading up on the fakeAsync and tick the answer here explains that:

tick() simulates the asynchronous passage of time.

I set up a plnkr example simulating this scenario.

Here, we call the getTimeout() method which calls an internal async task that has a timeout. In the test, we try wrapping it and calling tick() after calling the getTimeout() method.

counter.ts

getTimeout() {
  setTimeout(() => {
    console.log('timeout')
  },3000)
}

counter.specs.ts

it('timeout (fakeAsync/tick)', fakeAsync(() => {
    counter.getTimeout();
    tick();
}));

But, the unit test fails with the error "Error: 1 timer(s) still in the queue."

Does the issue here in the angular repo have anything to do with this?

Is it possible to use tick() this way to wait for a timeout function? Or is there another approach that I can use?

about 4 years ago · Santiago Trujillo
3 Respostas
Responde à pergunta

0

The purpose of fakeAsync is to control time within your spec. tick will not wait for any time as it is a synchronous function used to simulate the passage of time. If you want to wait until the asynchronous function is complete, you are going to need to use async and whenStable, however, in your example, the spec will take 3 seconds to pass so I wouldn't advise this.

The reason why the counter.spec.ts is failing is that you have only simulated the passage of 0 seconds (typically used to represent the next tick of the event loop). So when the spec completes, there are still mocked timers active and that fails the whole spec. It is actually working properly by informing you that a timeout has been mocked an is unhandled.

Basically, I think you are attempting to use fakeAsync and tick in ways for which they were not intended to be used. If you need to test a timeout the way that you have proposed, the simplest way would be to mock the setTimeout function yourself so that, regardless of the time used, you can just call the method.

EDITED I ran into a related issue where I wanted to clear the timers, and since it was not the part under test, I didn't care how long it took. I tried:

tick(Infinity);

Which worked, but was super hacky. I ended up going with

discardPeriodicTasks();

And all of my timers were cleared.

about 4 years ago · Santiago Trujillo Relatório

0

Try to add one or a combination of the following function calls to the end of your test:

    flush();
    flushMicrotasks();
    discardPeriodicTasks();
  1. flush (with optional maxTurns parameter) also flushes macrotasks. (This function is not mentionned in the Angular testing tutorial.)
  2. flushMicrotasks flushes the microtask queue.
  3. discardPeriodicTasks cancels "peridodic timer(s) still in the queue".

Timers in the queue do not necessarily mean that there's a problem with your code. For example, components that observe the current time may introduce such timers. If you use such components from a foreign library, you might also consider to stub them instead of "chasing timers".

For further understanding you may look at the javascript code of the fakeAsync function in zone-testing.js.

about 4 years ago · Santiago Trujillo Relatório

0

At the end of each test add:

 fixture.destroy();
 flush();
about 4 years ago · Santiago Trujillo Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda