I'm currently building an app and I have a routes file that looks like this.
const router = require('express').Router();
router.get('/', (req, res) => res.render('statics/home'));
router.get('/jobs', (req, res) => res.render('statics/jobs'));
router.get('/about-page', (req, res) => res.render('statics/about-page'));
router.get('/valves', (req, res) => res.render('statics/valves'));
router.all('*', (req, res) => res.notFound());
module.exports = router;
I am trying to figure out a way to refactor my routes and have a single route that accepts any string and then checks to see if a file exists matching it
Any help appreciated!
To easily handle static file, you can use express static, express will automatic route all file inside static folder
app = require('express')();
app.use('statics',express.static('statics'));
Something like this could work:
const router = require('express').Router();
const fs = require('fs');
router.get(':template', (req, res) => {
const tpl = req.param('template');
if (tpl) {
if (fs.existsSync('/path/to/templates/' + tpl + '.ext')) { // adjust the path and template extension
res.render('statics/' + tpl);
} else {
res.notFound();
}
} else {
res.render('statics/home');
}
});
router.all('*', (req, res) => res.notFound());
module.exports = router;
Or probably better approach would be to read the templates directory once and create routes based on its contents:
const router = require('express').Router();
const fs = require('fs');
const templates = fs.readdirSync('/path/to/templates');
templates.forEach(tpl => {
tpl = tpl.substring(tpl.lastIndexOf('/') + 1);
if (tpl === 'home') {
router.get('/', (req, res) => res.render('statics/home'))
} else {
router.get('/' + tpl, (req, res) => res.render('statics/' + tpl))
}
});
router.all('*', (req, res) => res.notFound());
module.exports = router;