I would like to match numbers greater than or equal to 1001(or '1001'). I tried the following pattern "^(^[1-9][0-9]{3,4}$)$". It matches from 1000 and above.
(?!^1000$)^[1-9]\d{3,}$
(?!^1000$) Except the number 1000^[1-9]\d{3,}$ Match 4 and more length numberslet regex = /(?!^1000$)^[1-9]\d{3,}$/;
console.log(regex.test("1000"));
console.log(regex.test("1001"));
console.log(regex.test("10000"));
console.log(regex.test("99995555"));See the regex demo