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Return more counts for same field

Given the following document:

[
  {
    "user": "A",
    "feedback":"like"
  },
  {
    "user": "B",
    "feedback":"dislike"
  },
  {
    "user": "C",
    "feedback":"like"
  },
  {
    "user": "D",
    "feedback":"like"
  },
  {
    "user": "E",
    "feedback":"dislike"
  },
]

I would like to get likes count and dislikes count.

In this case I would get {likesCount: 3, dislikesCount: 2}.

How can I achieve this using Mongoose?

about 4 years ago · Juan Pablo Isaza

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Encontrar trabalhos remotos

Answer 1 · 2022-06-24T16:59:56.416Z

Query

assuming that feedback and only be one of those 2 values
group by null (all collection 1 group)
(null is a common choice, the point is to group by a constant "_id" : "hello" would do the same)
and 2 sums, if its like add to likesCount 1, else add 0 (the same for the dislikes)

Playmongo

yourColl.aggregate(
[{"$group": 
   {"_id": null,
    "likesCount": 
     {"$sum": {"$cond": [{"$eq": ["$feedback", "like"]}, 1, 0]}},
    "dislikesCount": 
     {"$sum": {"$cond": [{"$eq": ["$feedback", "dislike"]}, 1, 0]}}}}])

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205

Return more counts for same field

1 Respostas

0

Encontrar trabalhos remotos

Andres GPT