Simplest Answer

array.sort(function(a,b){
  // Turn your strings into dates, and then subtract them
  // to get a value that is either negative, positive, or zero.
  return new Date(b.date) - new Date(a.date);
});

More Generic Answer

array.sort(function(o1,o2){
  if (sort_o1_before_o2)    return -1;
  else if(sort_o1_after_o2) return  1;
  else                      return  0;
});

Or more tersely:

array.sort(function(o1,o2){
  return sort_o1_before_o2 ? -1 : sort_o1_after_o2 ? 1 : 0;
});

Generic, Powerful Answer

Define a custom non-enumerable sortBy function using a Schwartzian transform on all arrays :

(function(){
  if (typeof Object.defineProperty === 'function'){
    try{Object.defineProperty(Array.prototype,'sortBy',{value:sb}); }catch(e){}
  }
  if (!Array.prototype.sortBy) Array.prototype.sortBy = sb;

  function sb(f){
    for (var i=this.length;i;){
      var o = this[--i];
      this[i] = [].concat(f.call(o,o,i),o);
    }
    this.sort(function(a,b){
      for (var i=0,len=a.length;i<len;++i){
        if (a[i]!=b[i]) return a[i]<b[i]?-1:1;
      }
      return 0;
    });
    for (var i=this.length;i;){
      this[--i]=this[i][this[i].length-1];
    }
    return this;
  }
})();

Use it like so:

array.sortBy(function(o){ return o.date });

If your date is not directly comparable, make a comparable date out of it, e.g.

array.sortBy(function(o){ return new Date( o.date ) });

You can also use this to sort by multiple criteria if you return an array of values:

// Sort by date, then score (reversed), then name
array.sortBy(function(o){ return [ o.date, -o.score, o.name ] };

See http://phrogz.net/JS/Array.prototype.sortBy.js for more details.

After correcting the JSON this should work for you now:

var array = [{id: 1, date:'Mar 12 2012 10:00:00 AM'}, {id: 2, date:'Mar 8 2012 08:00:00 AM'}];


array.sort(function(a, b) {
    var c = new Date(a.date);
    var d = new Date(b.date);
    return c-d;
});

Your data needs some corrections:

var array = [{id: 1, date: "Mar 12 2012 10:00:00 AM"},{id: 2, date: "Mar 28 2012 08:00:00 AM"}];

After correcting the data, you can use this piece of code:

function sortFunction(a,b){  
    var dateA = new Date(a.date).getTime();
    var dateB = new Date(b.date).getTime();
    return dateA > dateB ? 1 : -1;  
}; 

var array = [{id: 1, date: "Mar 12 2012 10:00:00 AM"},{id: 2, date: "Mar 28 2012 08:00:00 AM"}];
array.sort(sortFunction);​

@Phrogz answers are both great, but here is a great, more concise answer:

array.sort(function(a,b){return a.getTime() - b.getTime()});

Using the arrow function way

array.sort((a,b)=>a.getTime()-b.getTime());

found here: Sort date in Javascript

I'm going to add this here, as some uses may not be able to work out how to invert this sorting method.

To sort by 'coming up', we can simply swap a & b, like so:

your_array.sort ( (a, b) => {
      return new Date(a.DateTime) - new Date(b.DateTime);
});

Notice that a is now on the left hand side, and b is on the right, :D!

For anyone who is wanting to sort by date (UK format), I used the following:

//Sort by day, then month, then year
for(i=0;i<=2; i++){
    dataCourses.sort(function(a, b){

        a = a.lastAccessed.split("/");
        b = b.lastAccessed.split("/");

        return a[i]>b[i] ? -1 : a[i]<b[i] ? 1 : 0;
    }); 
}

You could use sortBy in underscore js.

http://underscorejs.org/#sortBy

Sample:

var log = [{date: '2016-01-16T05:23:38+00:00', other: 'sample'}, 
           {date: '2016-01-13T05:23:38+00:00',other: 'sample'}, 
           {date: '2016-01-15T11:23:38+00:00', other: 'sample'}];

console.log(_.sortBy(log, 'date'));

i was able to achieve sorting using below lines:

array.sort(function(a, b)
{
   if (a.DueDate > b.DueDate) return 1;
   if (a.DueDate < b.DueDate) return -1;
})

I have just taken the Schwartzian transform depicted above and made as function. It takes an array, the sorting function and a boolean as input:

function schwartzianSort(array,f,asc){
    for (var i=array.length;i;){
      var o = array[--i];
      array[i] = [].concat(f.call(o,o,i),o);
    }
    array.sort(function(a,b){
      for (var i=0,len=a.length;i<len;++i){
        if (a[i]!=b[i]) return a[i]<b[i]?asc?-1:1:1;
      }
      return 0;
    });
    for (var i=array.length;i;){
      array[--i]=array[i][array[i].length-1];
    }
    return array;
  }

function schwartzianSort(array, f, asc) {
  for (var i = array.length; i;) {
    var o = array[--i];
    array[i] = [].concat(f.call(o, o, i), o);
  }
  array.sort(function(a, b) {
    for (var i = 0, len = a.length; i < len; ++i) {
      if (a[i] != b[i]) return a[i] < b[i] ? asc ? -1 : 1 : 1;
    }
    return 0;
  });
  for (var i = array.length; i;) {
    array[--i] = array[i][array[i].length - 1];
  }
  return array;
}

arr = []
arr.push({
  date: new Date(1494434112806)
})
arr.push({
  date: new Date(1494434118181)
})
arr.push({
  date: new Date(1494434127341)
})

console.log(JSON.stringify(arr));

arr = schwartzianSort(arr, function(o) {
  return o.date
}, false)
console.log("DESC", JSON.stringify(arr));

arr = schwartzianSort(arr, function(o) {
  return o.date
}, true)
console.log("ASC", JSON.stringify(arr));

This should do when your date is in this format (dd/mm/yyyy).

  sortByDate(arr) {
    arr.sort(function(a,b){
      return Number(new Date(a.readableDate)) - Number(new Date(b.readableDate));
    });

    return arr;
  }

Then call sortByDate(myArr);

If like me you have an array with dates formatted like YYYY[-MM[-DD]] where you'd like to order more specific dates before less specific ones, I came up with this handy function:

function sortByDateSpecificity(a, b) {
  const aLength = a.date.length
  const bLength = b.date.length
  const aDate = a.date + (aLength < 10 ? '-12-31'.slice(-10 + aLength) : '')
  const bDate = b.date + (bLength < 10 ? '-12-31'.slice(-10 + bLength) : '')
  return new Date(aDate) - new Date(bDate)
}

Adding absolute will give better results

var datesArray =[
      {"some":"data1","date": "2018-06-30T13:40:31.493Z"},
      {"some":"data2","date": "2018-07-04T13:40:31.493Z"},
      {"some":"data3","date": "2018-06-27T13:40:54.394Z"}
   ]

var sortedJsObjects = datesArray.sort(function(a,b){ 
    return Math.abs(new Date(a.date) - new Date(b.date)) 
});

["12 Jan 2018" , "1 Dec 2018", "04 May 2018"].sort(function(a,b) {
    return new Date(a).getTime() - new Date(b).getTime()
})

Thank you Ganesh Sanap. sorting items by date field from old to new. Use it

 myArray = [{transport: "Air",
             load: "Vatican Vaticano",
             created: "01/31/2020"},
            {transport: "Air",
             load: "Paris",
             created: "01/30/2020"}] 

        myAarray.sort(function(a, b) {
            var c = new Date(a.created);
            var d = new Date(b.created);
            return c-d;
        });

I personally use following approach to sort dates.

let array = ["July 11, 1960", "February 1, 1974", "July 11, 1615", "October 18, 1851", "November 12, 1995"];

array.sort(function(date1, date2) {
   date1 = new Date(date1);
   date2 = new Date(date2);
   if (date1 > date2) return 1;
   if (date1 < date2) return -1;
})

Thanks for those brilliant answers on top. I have thought a slightly complicated answer. Just for those who want to compare different answers.

const data = [
    '2-2018', '1-2018',
    '3-2018', '4-2018',
    '1-2019', '2-2019',
    '3-2019', '4-2019',
    '1-2020', '3-2020',
    '4-2020', '1-2021'
]

let eachYearUniqueMonth = data.reduce((acc, elem) => {
    const uniqueDate = Number(elem.match(/(\d+)\-(\d+)/)[1])
    const uniqueYear = Number(elem.match(/(\d+)\-(\d+)/)[2])


    if (acc[uniqueYear] === undefined) {
        acc[uniqueYear] = []        
    } else{    
       if (acc[uniqueYear]  && !acc[uniqueYear].includes(uniqueDate)) {
          acc[uniqueYear].push(uniqueDate)
      }
    }

    return acc;
}, {})


let group = Object.keys(eachYearUniqueMonth).reduce((acc,uniqueYear)=>{
    eachYearUniqueMonth[uniqueYear].forEach(uniqueMonth=>{
    acc.push(`${uniqueYear}-${uniqueMonth}`)
  })
  
  return acc;
},[])

console.log(group);   //["2018-1", "2018-3", "2018-4", "2019-2", "2019-3", "2019-4", "2020-3", "2020-4"]

With ES6 arrow functions, you can further write just one line of concise code (excluding variable declaration).

Eg.:

var isDescending = true; //set to false for ascending
console.log(["8/2/2020","8/1/2020","8/13/2020", "8/2/2020"].sort((a,b) => isDescending ? new Date(b).getTime() - new Date(a).getTime() : new Date(a).getTime() - new Date(b).getTime()));

Since time does not exists with the above dates, the Date object will consider following default time for sorting:

00:00:00

The code will work for both ascending and descending sort. Just change the value of isDescending variable as required.

Strings with dates are comparable in JavaScript (if they are syntactically the same), e.g.:

'2020-12-01' < '2020-12-02' == true

This means you can use this expression in a custom sort function:

var arr = [{id:1, date:'2020-12-01'}, {id:1, date:'2020-12-15'}, {id:1, date:'2020-12-12'}]

function sortByDate(a, b) {
    if (a.date < b.date) {
        return 1;
    }
    if (a.date > b.date) {
        return -1;
    }
    return 0;
}

const sorted = arr.sort(sortByDate);
console.log(sorted);

arr is an array of object and each object has date_prop which is a date. You can sort it in descending/decreasing order like this

 arr = arr.sort(function (a, b) {
      var dateA = new Date(a.date_prop).getTime();
      var dateB = new Date(b.date_prop).getTime();
      return dateA < dateB ? 1 : -1; // ? -1 : 1 for ascending/increasing order
    });

I have an array of objects in which key 'time' contains the date in ISO format

Example - 2021-12-24T11:02:20.370705

arr.sort(function(a,b){return a.time > b.time ? 1 : a.time < b.time ? -1 : 0 });

Above worked for me like a charm!

Above answers are all good 😊, here is my implementation of sorting date in ES6 way, I'm using Date.parse (is global Date object) this will convert string representation of Date to number of milliseconds. Instead of instantiating new Date object every time.

var array = ["2021-08-10T07:24:30.087+0000" , "2021-09-30T07:24:30.087+0000", "2021-10-13T07:24:30.087+0000"];

// sorting with latest date
array.sort((a,b) => Date.parse(b) - Date.parse(a))