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Visualizaçõeslooping through Xml elements in indesign extendscript
I'm working on reading an xml via indesign script and create text boxes. Given this xml:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<project name="IPS300980XX_NEW" pagecount="50">
<styles>
<style nome="xxx" font="Arial" fontsize="10" bold="2" center="2" />
<style nome="yyy" font="Times" fontsize="24" bold="1" center="1" />
<style nome="zzzz" font="Helvetica" fontsize="22" bold="2" center="1" />
</styles>
</project>
</root>
I'm trying to loop through "style" nodes, without success. the code I'm using is the following (but i tried with several combinations of xmlelements, children, items, whatever :-( with no success).
"myxml" is the just opened xml document. Every variable has the expected values except "getTheStyle" (and consequently "test").
function creastili(){
var styles = myxml.project.styles;
var list = styles.child("style");
var getTheStyle = "";
for(var i = 0; i < list.length(); i++){
getTheStyle = list[i];
test = getTheStyle.toString();
//getTheStyle is always empty.
}
}
Any help would be really appreciated! Thank you very much.
·
Juan Pablo Isaza
1 Respostas
Responde à pergunta0
Perhaps you have to use toXMLString() instead of toString().
This code works for me:
var xml = '''<?xml version="1.0" encoding="UTF-8"?>
<root>
<project name="IPS300980XX_NEW" pagecount="50">
<styles>
<style nome="xxx" font="Arial" fontsize="10" bold="2" center="2" />
<style nome="yyy" font="Times" fontsize="24" bold="1" center="1" />
<style nome="zzzz" font="Helvetica" fontsize="22" bold="2" center="1" />
</styles>
</project>
</root>''';
function creastili(xml) {
var root = new XML(xml); // native Extendscript XML parser
var list = root.project.styles.children();
for(var i = 0; i < list.length(); i++){
var getTheStyle = list[i];
var test = getTheStyle.toXMLString();
alert(test);
}
}
creastili(xml);
You can get attributes of a 'style' this way:
var root = new XML(xml);
var style = root.project.styles.children()[0];
var name = style.@nome;
var font = style.@font;
var size = style.@fontsize;
// etc
alert([name, font, size].join('\n'));
·
Juan Pablo Isaza
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