Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

157
Visualizações
How to check current date is available or not in the date array in typescript

How to check current date is available or not in the date array in typescript. Tried to check with below code, If current is available in between the array dates, still its giving result as false. Kindly suggest me the solution.

let time1= ['5:00:00 PM','5:59:59 PM'];
const dateCheck = new Date().toLocaleTimeString('en-US');
const status = time1.includes(dateCheck) ?true:false;
console.log(status);

about 4 years ago · Juan Pablo Isaza
3 Respostas
Responde à pergunta

0

include only checks for an exact match on the array, between is not included

to use include you would have to populate the array with every possible time between the 2,

however you can use > >= and < <= to check for between

const dateCheck:date = new Date().toLocaleTimeString('en-US');
const time1:string[] = ['12:00:00 PM','12:59:59 PM'];

const status: boolean = (time1[0]<=dateCheck && time1[1]>=dateCheck)
console.log(dateCheck,status);

//output "12:56:13 PM", true

this is using an alphabetic compare not a date compare so will yield odd results, your should really convert to timestamps or compare the date components, to compare properly eg

const dateCheck:date = new Date()
const time1 = [{
    hour:12,
  minute:0
},{
    hour:17,
  minute:59
}]

//convert to number of minutes since midnight so you can use a numeric compare
const dayMins = dateCheck.getHours()*60+ dateCheck.getMinutes()
const start = time1[0].hour*60+ time1[0].minute
const end = time1[1].hour*60+ time1[1].minute

const status = (
    dayMins>=start &&  dayMins<=end
)
console.log(dateCheck.toLocaleTimeString(),status)
about 4 years ago · Juan Pablo Isaza Relatório

0

let times = ['5:00:00 PM', '5:59:59 PM'];

startTime = new Date('2022-01-01 ' + times[0]).getTime()
endTime = new Date('2022-01-01 ' + times[1]).getTime()


testTime = new Date('2022-01-01 ' + '5:30:00 PM').getTime()
const isBetween = testTime > startTime && testTime < endTime;

about 4 years ago · Juan Pablo Isaza Relatório

0

A lot of the other answers here use string-based comparisons. To ensure the correct results, you should instead use numeric comparisons. Especially when checking between different days such as between 10PM and 2AM.

function checkTime(timeCheck, timeRange) {
    const datePart = '2000-01-01 ', // used to anchor times to the same date
        d0 = new Date(datePart + timeRange[0]).getTime(),
        d1 = new Date(datePart + timeRange[1]).getTime(),
        dToCheck = new Date(datePart + (typeof timeCheck === 'string' ? timeCheck : timeCheck.toLocaleTimeString('en-US'))).getTime();

    if (isNaN(d0) || isNaN(d1) || isNaN(dToCheck)) throw new TypeError('invalid time format');

    return d0 < d1
        ? d0 <= dToCheck && dToCheck <= d1  // handle times on the same day
        : d1 <= dToCheck || dToCheck <= d0; // handle times on different days
}

const timeRange = ['5:00:00 PM','5:59:59 PM'];

checkTime('5:15:00 PM', timeRange); // true
checkTime('5:15 PM', timeRange); // true
checkTime('5:15:00 AM', timeRange); // false
checkTime('5:15 AM', timeRange); // false
checkTime(new Date().toLocaleTimeString('en-US'), timeRange); // depends
checkTime(new Date(), timeRange); // depends
checkTime(new Date('2021-01-01T12:00:00Z'), timeRange); // depends on timezone

If you want to perform this check against many items, you should instead use currying to squeeze out some extra performance by pre-calculating the range to compare against.

function buildCheckTime(startTime, endTime) {
    const datePart = '2000-01-01 ', // used to anchor times to the same date
        d0 = new Date(datePart + startTime).getTime(),
        d1 = new Date(datePart + endTime).getTime();

    if (isNaN(d0) || isNaN(d1)) throw new TypeError('invalid time format');

    return d0 < d1
        ? function(timeCheck) { // handle times on the same day
            const dToCheck = new Date(datePart + (typeof timeCheck === 'string' ? timeCheck : timeCheck.toLocaleTimeString('en-US'))).getTime();

            if (isNaN(dToCheck)) throw new TypeError('invalid time format');

            return d0 <= dToCheck && dToCheck <= d1;
        }
        : function (timeCheck) { // handle times on different days
            const dToCheck = new Date(datePart + (typeof timeCheck === 'string' ? timeCheck : timeCheck.toLocaleTimeString('en-US'))).getTime();

            if (isNaN(dToCheck)) throw new TypeError('invalid time format');

            return d1 <= dToCheck || dToCheck <= d0;
        }
}

const checkTime = buildCheckTime('5:00:00 PM','5:59:59 PM');

checkTime('5:15:00 PM'); // true
checkTime('5:15 PM'); // true
checkTime('5:15:00 AM'); // false
checkTime('5:15 AM'); // false
checkTime(new Date().toLocaleTimeString('en-US')); // depends
checkTime(new Date()); // depends
checkTime(new Date('2021-01-01T12:00:00Z')); // depends on timezone
about 4 years ago · Juan Pablo Isaza Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda