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VisualizaçõesUpload File in Angular through an API which accepts File as Blob and requires Multi part Form Data
I am building a form in angular which is used to upload a file and I have a third party API that I need to call which accepts Multi part form data and file as blob. Can you please tell me how can I do that? I have this code for now?
HTML
<form [formGroup]="customerFileGroup" (submit)="submit($event)">
<div>
<input
formControlName="file"
type="file"
accept=".csv,text/plain, text/csv, text/html"
(onSelection)="changeFile($event)"
/>
</div>
<button>Submit</button
</form>
Typescript
export class CustomerFile{
constructor(private readonly _fb: FormBuilder) {}
const customerFileGroup: FormGroup = this._fb.group({
file: this._fb.control(null),
});
submit(e: Event): void {
e.preventDefault();
const formData = new FormData();
formData.append('file', this.fileUploadGroup.value);
// this.customerFileService.uploadFile(formData.file?);
What should I send here because the API requires file as blob now
}
File/API
public uploadFile(
file: Blob
)
{
// Black box for me
}
Swagger
I am trying to understand what do I need to pass in the service so it is multi part form data but the request body of file is a blob. I am using Angular 10. Let me know if more info is required
If I pass the formdata, I get the following error:
Argument of type 'FormData' is not assignable to parameter of type 'Blob'
·
Juan Pablo Isaza
1 Respostas
Responde à pergunta0
You shouldn't use ngModel or formControl to get file, you have to store the file in variable manually when file changes, see the example below
<form [formGroup]="customerFileGroup" (submit)="submit($event)">
<div>
<input
formControlName="file"
type="file"
accept=".csv,text/plain, text/csv, text/html"
(change)="changeFile($event)" <!-- Change event name to "change" -->
/>
</div>
<button>Submit</button>
</form>
export class CustomerFile{
...
fileToUpload: FileList;
changeFile(evt) {
this.fileToUpload = evt.target.files[0];
}
submit(e: Event): void {
e.preventDefault();
const formData = new FormData();
formData.append('file', this.fileToUpload);
this.customerFileService.uploadFile(formData);
}
}
export class CustomerFileService {
...
public uploadFile(payload: FormData) {
return this.http.post('<API_URL>',payload);
}
}
·
Juan Pablo Isaza
Relatório
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