0
150
Visualizaçõeskeep array order when getting values from json
For input of var idx = [4, 6, 5]:
i: 0 id: 4 rating: 999
i: 2 id: 5 rating: 333
i: 1 id: 6 rating: 666
Desired result:
i: 0 id: 4 rating: 999
i: 1 id: 6 rating: 666
i: 2 id: 5 rating: 333
var data = [{
"id": 1,
"rating": 55
},
{
"id": 2,
"rating": 22
},
{
"id": 3,
"rating": 111
},
{
"id": 4,
"rating": 999
},
{
"id": 5,
"rating": 333
},
{
"id": 6,
"rating": 666
}
];
var idx = [4, 6, 5];
$.each(data, function() {
for (var i = 0; i < idx.length; ++i) {
if (idx[i] == this.id) {
console.log('i: ' + i + ' id: ' + this.id + ' rating: ' + this.rating);
}
}
});
·
Juan Pablo Isaza
3 Respostas
Responde à pergunta0
Your problem solves by Array.map Just map your idx values:
var data = [{
"id": 1,
"rating": 55
},
{
"id": 2,
"rating": 22
},
{
"id": 3,
"rating": 111
},
{
"id": 4,
"rating": 999
},
{
"id": 5,
"rating": 333
},
{
"id": 6,
"rating": 666
}
];
var idx = [4, 6, 5];
var mappedData = idx.map(function(idx) {
return data.find(function(dataItem) {
return dataItem.id === idx
})
})
mappedData.forEach(function(v) {
console.log('id: ' + v.id + ' rating: ' + v.rating);
})
·
Juan Pablo Isaza
Relatório
0
You were just looping with the wrong list :)
var data = [{
"id": 1,
"rating": 55
},
{
"id": 2,
"rating": 22
},
{
"id": 3,
"rating": 111
},
{
"id": 4,
"rating": 999
},
{
"id": 5,
"rating": 333
},
{
"id": 6,
"rating": 666
}
];
var idx = [4, 6, 5];
idx.forEach((id, index) => {
const myData = data.find(x => x.id == id);
console.log(`i:${index} id:${myData.id} rating: ${myData.rating}`)
});
·
Juan Pablo Isaza
Relatório
0
Try the following:
var data = [{
"id": 1,
"rating": 55
},
{
"id": 2,
"rating": 22
},
{
"id": 3,
"rating": 111
},
{
"id": 4,
"rating": 999
},
{
"id": 5,
"rating": 333
},
{
"id": 6,
"rating": 666
}
];
var idx = [4, 6, 5];
for (let i = 0; i < idx.length; i++) {
const rating_ind = data.findIndex(e => e.id == idx[i])
if (rating_ind > -1) {
console.log('i: ' + i + ' id: ' + idx[i] + ' rating: ' + data[rating_ind].rating);
}
}
·
Juan Pablo Isaza
Relatório
Responde à pergunta