So I have this definition:
sealed interface ParseResult<out R> {
data class Success<R>(val value: R) : ParseResult<R>
data class Failure(val original: String, val error: Throwable) : ParseResult<Nothing>
}
I want to wrap certain elements in a Success. And I know I can do it like this...
list.map{ParseResult.Success(it)}
But is there a way to use a constructor reference?
list.map(ParseResult::Success) //this won't compile
You can use a constructor reference if you add an import:
import somepackage.ParseResult.Success
Or even a typealias:
typealias Success<R> = ParseResult.Success<R>
Then you can do:
list.map(::Success)
The idea here is to make ParseResult.Success referrable by a simple name.
Not being able to do ParseResult::Success does look like a bug to me though. Compare:
class Outer {
class Nested
}
class OuterGeneric<T> {
class Nested
}
fun main() {
val x = Outer::Nested // works
val y = OuterGeneric::Nested // error
}