I'm a noob when it comes to JS and am trying to figure out how to return a single value instead of an object when using the .find() function.
Example:
var obj = [
{ name: 'Max', age: 23 },
{ name: 'John', age: 20 },
{ name: 'Caley', age: 18 }
];
var found = obj.find(e => e.name === 'John');
console.log(found);This will output { name: 'John', age: 20 }
I want it to output John's age (ie: 20) as a string.
What am I missing?
Simple add ?.age to your found variable.
var obj = [
{ name: 'Max', age: 23 },
{ name: 'John', age: 20 },
{ name: 'Caley', age: 18 }
];
var found = obj.find(e => e.name === 'John')?.age; // Using ?. incase value isnt found.
console.log(found);
You also mention you need it as a string, you can do achieve by wrapping the found var in the String function like so...
var obj = [
{ name: 'Max', age: 23 },
{ name: 'John', age: 20 },
{ name: 'Caley', age: 18 }
];
var found = String(obj.find(e => e.name === 'John')?.age);
console.log(found);
.find function return you an object so you can just do something like this
var age = obj.find(e => e.name === "John").age