Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

331
Visualizações
Cómo verificar si una clave de objeto está en otro objeto de objetos

Tengo los siguientes objetos:

 const allMembers = { "-Lz8YxHiwp8QZW3TqAFn": { "first": "foo", "last": "bar", "uid": "-Lz8YxHiwp8QZW3TqAFn" }, "-Lz8YxHqQXWoaGOFRLrO": { "first": "foo", "last": "bar", "uid": "-Lz8YxHqQXWoaGOFRLrO" }, "-Lz8YxHsMItaaTVNyQRE": { "first": "foo", "last": "bar", "uid": "-Lz8YxHsMItaaTVNyQRE" }, "-Lz8YxHwuVBMWl0Go6C5": { "first": "foo", "last": "bar", "uid": "-Lz8YxHwuVBMWl0Go6C5" }, "-Lz8YxHy0S-QkDaE1PkX": { "first": "foo", "last": "bar", "uid": "-Lz8YxHy0S-QkDaE1PkX" }, } const attendanceData = { "-Lz8YxHiwp8QZW3TqAFn": true, "-Lz8YxHqQXWoaGOFRLrO": true, "-Lz8YxHsMItaaTVNyQRE": true, "-Lz8YxHwuVBMWl0Go6C5": false, "-Lz8YxHy0S-QkDaE1PkX": true, "-Lz8YxIFA1XGVmaNfNr3": false, "-Lz8YxIJVZnIIj7RgEzg": false, }

Necesito limpiar todos los miembros para regresar solo si se encuentra como verdadero en los datos de asistencia. Aquí está mi intento, pero obviamente no funciona. Además, la forma en que lo estoy haciendo tiene que repetir el primero sobre las otras veces.

 const membersHere = Object.keys(allMembers).filter(memEl => Object.keys(attendanceData).find(attendEl => memEl == attendEl));
about 4 years ago · Juan Pablo Isaza
3 Respostas
Responde à pergunta

0

  • Convierta el objeto allMembers en una matriz de pares de valores clave mediante Object.entries .

  • Filtre los elementos que tienen valor true usando Array.prototype.filter .

  • Transforme la matriz nuevamente en un objeto usando Object.fromEntries .

 const allMembers = {'-Lz8YxHiwp8QZW3TqAFn': {first: 'foo',last: 'bar',uid: '-Lz8YxHiwp8QZW3TqAFn'},'-Lz8YxHqQXWoaGOFRLrO': {first: 'foo',last: 'bar',uid: '-Lz8YxHqQXWoaGOFRLrO'},'-Lz8YxHsMItaaTVNyQRE': {first: 'foo',last: 'bar',uid: '-Lz8YxHsMItaaTVNyQRE'},'-Lz8YxHwuVBMWl0Go6C5': {first: 'foo',last: 'bar',uid: '-Lz8YxHwuVBMWl0Go6C5'},'-Lz8YxHy0S-QkDaE1PkX': {first: 'foo',last: 'bar',uid: '-Lz8YxHy0S-QkDaE1PkX'}}, attendanceData = {'-Lz8YxHiwp8QZW3TqAFn': true,'-Lz8YxHqQXWoaGOFRLrO': true,'-Lz8YxHsMItaaTVNyQRE': true,'-Lz8YxHwuVBMWl0Go6C5': false,'-Lz8YxHy0S-QkDaE1PkX': true,'-Lz8YxIFA1XGVmaNfNr3': false,'-Lz8YxIJVZnIIj7RgEzg': false}, filteredMembers = Object.fromEntries( Object.entries(allMembers).filter(([k]) => attendanceData[k]) ); console.log(filteredMembers);

También puedes hacerlo usando Array.prototype.reduce

 const allMembers = {'-Lz8YxHiwp8QZW3TqAFn': {first: 'foo',last: 'bar',uid: '-Lz8YxHiwp8QZW3TqAFn'},'-Lz8YxHqQXWoaGOFRLrO': {first: 'foo',last: 'bar',uid: '-Lz8YxHqQXWoaGOFRLrO'},'-Lz8YxHsMItaaTVNyQRE': {first: 'foo',last: 'bar',uid: '-Lz8YxHsMItaaTVNyQRE'},'-Lz8YxHwuVBMWl0Go6C5': {first: 'foo',last: 'bar',uid: '-Lz8YxHwuVBMWl0Go6C5'},'-Lz8YxHy0S-QkDaE1PkX': {first: 'foo',last: 'bar',uid: '-Lz8YxHy0S-QkDaE1PkX'}}, attendanceData = {'-Lz8YxHiwp8QZW3TqAFn': true,'-Lz8YxHqQXWoaGOFRLrO': true,'-Lz8YxHsMItaaTVNyQRE': true,'-Lz8YxHwuVBMWl0Go6C5': false,'-Lz8YxHy0S-QkDaE1PkX': true,'-Lz8YxIFA1XGVmaNfNr3': false,'-Lz8YxIJVZnIIj7RgEzg': false}, filteredMembers = Object.entries(allMembers).reduce( (r, [k, v]) => (attendanceData[k] && (r[k] = v), r), {} ); console.log(filteredMembers);

Otra documentación relevante:

  • Operador de coma (,)
about 4 years ago · Juan Pablo Isaza Relatório

0

Puedes usar el método reduce :

 const allMembers = { "-Lz8YxHiwp8QZW3TqAFn": { "first": "foo", "last": "bar", "uid": "-Lz8YxHiwp8QZW3TqAFn" }, "-Lz8YxHqQXWoaGOFRLrO": { "first": "foo", "last": "bar", "uid": "-Lz8YxHqQXWoaGOFRLrO" }, "-Lz8YxHsMItaaTVNyQRE": { "first": "foo", "last": "bar", "uid": "-Lz8YxHsMItaaTVNyQRE" }, "-Lz8YxHwuVBMWl0Go6C5": { "first": "foo", "last": "bar", "uid": "-Lz8YxHwuVBMWl0Go6C5" }, "-Lz8YxHy0S-QkDaE1PkX": { "first": "foo", "last": "bar", "uid": "-Lz8YxHy0S-QkDaE1PkX" }, } const attendanceData = { "-Lz8YxHiwp8QZW3TqAFn": true, "-Lz8YxHqQXWoaGOFRLrO": true, "-Lz8YxHsMItaaTVNyQRE": true, "-Lz8YxHwuVBMWl0Go6C5": false, "-Lz8YxHy0S-QkDaE1PkX": true, "-Lz8YxIFA1XGVmaNfNr3": false, "-Lz8YxIJVZnIIj7RgEzg": false, } const reduced = Object.entries(allMembers).reduce((data, [key, value]) => { if (attendanceData[key] ?? false) data[key] = value; return data; }, {}); console.log(reduced);

about 4 years ago · Juan Pablo Isaza Relatório

0

Puede combinar Object.keys() , Array.prototype.filter() y Array.prototype.reduce()

Código:

 const allMembers = {'-Lz8YxHiwp8QZW3TqAFn': {first: 'foo',last: 'bar',uid: '-Lz8YxHiwp8QZW3TqAFn',},'-Lz8YxHqQXWoaGOFRLrO': {first: 'foo',last: 'bar',uid: '-Lz8YxHqQXWoaGOFRLrO',},'-Lz8YxHsMItaaTVNyQRE': {first: 'foo',last: 'bar',uid: '-Lz8YxHsMItaaTVNyQRE',},'-Lz8YxHwuVBMWl0Go6C5': {first: 'foo',last: 'bar',uid: '-Lz8YxHwuVBMWl0Go6C5',},'-Lz8YxHy0S-QkDaE1PkX': {first: 'foo',last: 'bar',uid: '-Lz8YxHy0S-QkDaE1PkX',},} const attendanceData = {'-Lz8YxHiwp8QZW3TqAFn': true,'-Lz8YxHqQXWoaGOFRLrO': true,'-Lz8YxHsMItaaTVNyQRE': true,'-Lz8YxHwuVBMWl0Go6C5': false,'-Lz8YxHy0S-QkDaE1PkX': true,'-Lz8YxIFA1XGVmaNfNr3': false,'-Lz8YxIJVZnIIj7RgEzg': false,} const result = Object .keys(allMembers) .filter((k) => attendanceData[k]) .reduce((a, k) => (a[k] = allMembers[k], a), {}) console.log(result)

about 4 years ago · Juan Pablo Isaza Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda