Given a type T:

type T = {
  akey: string | number | undefined
}

If I check specifically for it

const fun = (p: T) => {
  if(!p.akey) return
  p.akey.toString()
}

Typescript understands that akey can't be undefined.

If I do it generically though:

const fun2 = (p: T) => {
  if(Object.values(p).includes(undefined)) return
  p.akey.toString()
}

It does not: Object is possibly 'undefined'.

How can I make typescript understand so I don't have to do:

p.akey!.toString()